Question

输入列表

[(1, 0, 3), '21:40:44', (1, 3, 9), (1, 4, 6), '.273']
[(1, 0, 3), '21:43:37', (1, 3, 9), (1, 4, 6), '.060']
[(1, 0, 3), '21:45:27', (1, 3, 9), (1, 4, 6), '.410']

结果应为：

[(1, 0, 3), ['21:40:44', '21:43:37', '21:45:27'], (1, 3, 9), (1, 4, 6), ['.273', '.060', '.410']

目标是减少重复项，一列中的唯一元素应存储在列表中。

Answer 1

如何使用zip。它将合并3个列表，并为您提供重复的输出。以后使用set删除重复项。并且由于您不希望仅对单个元素使用元组列表，请使用list(set(x))[0] if len(set(x))==1 else list(set(x))

a=[(1, 0, 3), '21:40:44', (1, 3, 9), (1, 4, 6), '.273']
b=[(1, 0, 3), '21:43:37', (1, 3, 9), (1, 4, 6), '.060']
c=[(1, 0, 3), '21:45:27', (1, 3, 9), (1, 4, 6), '.410']
l=[list(set(x))[0] if len(set(x))==1 else list(set(x)) for x in list(zip(a,b,c))]
print(l)
>>>[(1, 0, 3), ['21:45:27', '21:40:44', '21:43:37'], (1, 3, 9), (1, 4, 6), ['.060', '.273', '.410']]

Answer 2

最简单的方法是：

in_data = [
[(1, 0, 3), '21:40:44', (1, 3, 9), (1, 4, 6), '.273'],
[(1, 0, 3), '21:43:37', (1, 3, 9), (1, 4, 6), '.060'],
[(1, 0, 3), '21:45:27', (1, 3, 9), (1, 4, 6), '.410']
]
res = []
for i in range(len(in_data[0])):
    data = list(set([x[i] for x in in_data ]))
    data = data[0] if len(data) == 1 else data
    res.append(data)
print(res)
>>> [(1, 0, 3), ['21:43:37', '21:40:44', '21:45:27'], (1, 3, 9), (1, 4, 6), ['.273', '.060', '.410']]

合并重复列表

2 个答案: