在PyQt5应用程序中,我有一个QMenu。我要使菜单打开后,用户可以使用键1、2、3等在菜单中选择选项1、2、3等。但是,我在设置快捷方式或让快捷方式对按键做出反应时遇到麻烦。
我已经从this网站上举了一个例子,并对其进行了一些微调以显示我的问题。我尝试在addAction函数中分配快捷方式,但这不起作用。
我尝试创建常规的QShortcut,但是当菜单打开时,它们不再响应。我注意到我可以使用向上和向下箭头更改所选的选项,然后使用Enter键确认选择,因此QMenu可以捕获按键。但是如何分配自己的快捷方式?
from PyQt5 import QtGui
from PyQt5.QtWidgets import QApplication, QMainWindow, QMenu
import sys
class Window(QMainWindow):
def __init__(self):
super().__init__()
self.title = "PyQt5 Context Menu"
self.top = 200
self.left = 500
self.width = 400
self.height = 300
self.InitWindow()
def InitWindow(self):
self.setWindowIcon(QtGui.QIcon("icon.png"))
self.setWindowTitle(self.title)
self.setGeometry(self.left, self.top, self.width, self.height)
self.show()
def contextMenuEvent(self, event):
contextMenu = QMenu(self)
newAct = contextMenu.addAction("New", self.triggered, shortcut='A')
openAct = contextMenu.addAction("Open", self.triggered2, shortcut='B')
quitAct = contextMenu.addAction("Quit", self.triggered3, shortcut='C')
action = contextMenu.exec_(self.mapToGlobal(event.pos()))
if action == quitAct:
self.close()
def triggered(self):
print("triggered 1")
def triggered2(self):
print("triggered 2")
def triggered3(self):
print("triggered 3")
App = QApplication(sys.argv)
window = Window()
sys.exit(App.exec())
答案 0 :(得分:1)
答案 1 :(得分:0)
QKeySequence class
封装了快捷方式所使用的键序列。
更多... https://doc.qt.io/qt-5/qkeysequence.html
尝试一下:
import sys
from PyQt5 import QtGui
from PyQt5.QtWidgets import QApplication, QMainWindow, QMenu
class Window(QMainWindow):
def __init__(self):
super().__init__()
self.title = "PyQt5 Context Menu"
self.top = 200
self.left = 500
self.width = 400
self.height = 300
self.InitWindow()
def InitWindow(self):
self.setWindowIcon(QtGui.QIcon("icon.png"))
self.setWindowTitle(self.title)
self.setGeometry(self.left, self.top, self.width, self.height)
self.show()
def contextMenuEvent(self, event):
contextMenu = QMenu(self)
# newAct = contextMenu.addAction("New", self.triggered, shortcut='A')
newAct = contextMenu.addAction(
"New (&A)", self.triggered, shortcut=QtGui.QKeySequence.New) # +++
openAct = contextMenu.addAction(
"Open (&B)", self.triggered2, shortcut=QtGui.QKeySequence.Open) # +++
quitAct = contextMenu.addAction(
"Quit (&C)", self.triggered3, shortcut=QtGui.QKeySequence.Quit) # +++
action = contextMenu.exec_(self.mapToGlobal(event.pos()))
if action == quitAct:
self.close()
def triggered(self):
print("triggered 1")
def triggered2(self):
print("triggered 2")
def triggered3(self):
print("triggered 3")
App = QApplication(sys.argv)
window = Window()
sys.exit(App.exec())