在Vue中,我有一个带有此data(TempId)的数组:
[{"id":47},{"id":45},{"id":48}]
第二个与此数组:
multiprices: [
{
id: 45,
name: "",
price: "2600000",
},
{
id: 46,
name: "",
price: "2600000",
},
{
id: 47,
name: "",
price: "2600000",
},
{
id: 48,
name: "",
price: "2600000",
}
],
我想找到并删除第二个数组的项目,然后将其复制到新数据中(在本示例中为id 46)
答案 0 :(得分:0)
您可以使用第一个数组的id列表中的element条件过滤第二个数组
const tempObj = [{ id: 47 }, { id: 45 }, { id: 48 }]
const tempId = tempObj.map(({ id }) => id)
const multiprices = [
{
id: 45,
name: "",
price: "2600000",
},
{
id: 46,
name: "",
price: "2600000",
},
{
id: 47,
name: "",
price: "2600000",
},
{
id: 48,
name: "",
price: "2600000",
},
]
const res = multiprices.filter((multiprice) => !tempId.includes(multiprice.id))
console.log(res)