在做乐透检查程序时,约束之一是 不使用循环 或 数据结构,例如数组,列表等< / strong> 我编写了以下代码,以检查用户给出的3个条目( draw1,draw2,draw3 )是否等于所生成的7个随机数中的任何一个通过程序( random1,random2,random3,... )。
if (random1==draw1 || random2==draw1 || random3==draw1 || random4==draw1|| random5==draw1
|| random6==draw1 || random7==draw1)
{
if(random1==draw2 || random2==draw2 || random3==draw2 || random4==draw2|| random5==draw2
|| random6==draw2 || random7==draw2)
{
if(random1==draw3 || random2==draw3 || random3==draw3 || random4==draw3|| random5==draw3
|| random6==draw3 || random7==draw3)
{
str = str +'\n' + "The following 3 matches were found:" +'\n'+ draw1 + " " + draw2
+ " " + draw3 ;
}else
{
str = str + '\n' + "The following 2 matches were found:" + '\n' + draw1 + " " + draw2;
}
}else if (random1==draw3 || random2==draw3 || random3==draw3 || random4==draw3|| random5==draw3
|| random6==draw3 || random7==draw3)
{
str = str + '\n' + "The following 2 matches were found:" + '\n' + draw1 + " " + draw3 ;
}
else
{
str = str + '\n' + "The following 1 matches were found:" + '\n' + draw1;
}
}else if (random1==draw2 || random2==draw2 || random3==draw2 || random4==draw2|| random5==draw2
|| random6==draw2 || random7==draw2)
{
if(random1==draw3 || random2==draw3 || random3==draw3 || random4==draw3|| random5==draw3
|| random6==draw3 || random7==draw3)
{
str = str + '\n' + "The following 2 matches were found:" + '\n' + draw2 + " " + draw3;
}
else
{
str = str + '\n' + "The following 1 matches were found:" + '\n' + draw2;
}
}
else if (random1==draw3 || random2==draw3 || random3==draw3 || random4==draw3|| random5==draw3
|| random6==draw3 || random7==draw3)
{
str = str + '\n' + "The following 1 matches were found:" + '\n' + draw3;
}
else
{
str = str + '\n' + "The following 0 matches were found:" ;
}
如何进行优化,最重要的是优化只会增加可读性,还是会提高程序效率?
答案 0 :(得分:0)
使用集,这将提高可读性。
Set<Integer> luckyNumbers = new HashSet<>();
//Add your numbers to the set
//Integer i = ...
//luckyNumbers.add(i);
Set<Integer> drawNumbers = new HashSet<>();
//Integer i = ...
//drawNumbers.add(i);
Set<Integer> matchNumbers = new HashSet<>(luckyNumbers);
matchNumbers.retainAll(drawNumbers);
//In matchNumbers will be the intersection of the previous sets.
//There you can get the size of the intersection set or its content to show the
//matches
如果要在此部分使用循环,可以执行以下操作:
System.out.println("Number of matches: " + matchNumbers.size());
for(Integer matchNumber : matchNumbers){
System.out.println("Match number: " + matchNumber);
}
答案 1 :(得分:0)
尝试一下。
static boolean equalsAny(int base, int... comparisons) {
for (int c : comparisons)
if (base == c)
return true;
return false;
}
您可以重写
if (random1 == draw1 || random2 == draw1 || random3 == draw1 || random4 == draw1 || random5 == draw1
|| random6 == draw1 || random7 == draw1) {
到
if (equalsAny(draw1, random1, random2, random3, random4, random5, random6, random7)) {