任何人都可以帮助我如何在动态中重建这个吗？
<?php
error_reporting ( E_ALL );
$menu = array
(
1 => array
(
'text' => 'Articles',
'class' => 'articles',
'link' => '#',
'show_condition'=> TRUE,
'parent' => 0
),
2 => array
(
'text' => 'Users',
'class' => 'users',
'link' => '#',
'show_condition'=> TRUE,
'parent' => 0
),
3 => array
(
'text' => 'Groups',
'class' => 'groups',
'link' => '#',
'show_condition'=> TRUE,
'parent' => 0
),
4 => array
(
'text' => 'Settings',
'class' => 'settings',
'link' => '#',
'show_condition'=> TRUE,
'parent' => 0
),
5 => array
(
'text' => 'Add new',
'class' => 'add_article',
'link' => '#',
'show_condition'=> TRUE,
'parent' => 1
),
6 => array
(
'text' => 'Categories',
'class' => 'categories',
'link' => '#',
'show_condition'=> TRUE,
'parent' => 1
),
7 => array
(
'text' => 'Add new',
'class' => 'add_user',
'link' => '#',
'show_condition'=> TRUE,
'parent' => 2
),
8 => array
(
'text' => 'Delete',
'class' => 'delete',
'link' => '#',
'show_condition'=> TRUE,
'parent' => 1
),
9 => array
(
'text' => 'Show',
'class' => 'show',
'link' => '#',
'show_condition'=> TRUE,
'parent' => 2
),
10 => array
(
'text' => 'Last created',
'class' => 'last',
'link' => '#',
'show_condition'=> TRUE,
'parent' => 9
),
11 => array
(
'text' => 'First created',
'class' => 'first',
'link' => '#',
'show_condition'=> TRUE,
'parent' => 9
),
12 => array
(
'text' => 'All',
'class' => 'all',
'link' => '#',
'show_condition'=> TRUE,
'parent' => 9
),
13 => array
(
'text' => 'None',
'class' => 'none',
'link' => '#',
'show_condition'=> TRUE,
'parent' => 9
)
);
function build_menu ( $menu )
{
$out = '<div class="container4">' . "\n";
$out .= ' <div class="menu4">' . "\n";
$out .= "\n".'<ul>' . "\n";
for ( $i = 1; $i <= count ( $menu ); $i++ )
{
if ( is_array ( $menu [ $i ] ) )
{ //must be by construction but let's keep the errors home
if ( $menu [ $i ] [ 'show_condition' ] && $menu [ $i ] [ 'parent' ] == 0 ) { //are we allowed to see this menu?
$out .= '<li class="' . $menu [ $i ] [ 'class' ] . '"><a href="' . $menu [ $i ] [ 'link' ] . '">';
$out .= $menu [ $i ] [ 'text' ];
$out .= '</a>';
$out .= get_childs ( $menu, $i );
$out .= '</li>' . "\n";
}
}
else
{
die ( sprintf ( 'menu nr %s must be an array', $i ) );
}
}
$out .= '</ul>'."\n";
$out .= "\n\t" . '</div>';
return $out . "\n\t" . '</div>';
}
function get_childs ( $menu, $el_id )
{
$has_subcats = FALSE;
$out = '';
$out .= "\n".' <ul>' . "\n";
for ( $i = 1; $i <= count ( $menu ); $i++ )
{
if ( $menu [ $i ] [ 'show_condition' ] && $menu [ $i ] [ 'parent' ] == $el_id )
{ //are we allowed to see this menu?
$has_subcats = TRUE;
$add_class = ( get_childs ( $menu, $i ) != FALSE ) ? ' subsubl' : '';
$out .= '<li class="' . $menu [ $i ] [ 'class' ] . $add_class . '"><a href="' . $menu [ $i ] [ 'link' ] . '">';
$out .= $menu [ $i ] [ 'text' ];
$out .= '</a>';
$out .= get_childs ( $menu, $i );
$out .= '</li>' . "\n";
}
}
$out .= ' </ul>'."\n";
return ( $has_subcats ) ? $out : FALSE;
}
?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>Dynamic PHP/CSS menu by roScripts</title>
<link href="css/styles.css" rel="stylesheet" type="text/css" />
</head>
<body>
<div style="width:700px;margin:100px auto">
<h2>Dynamic PHP/CSS menu by <a href="http://www.roscripts.com" title="programming articles and tutorials" target="_blank">roScripts</a></h2>
<?= build_menu ( $menu ) ?>
</div>
</body>
</html>
我的数据库：
mysql> describe menuSystem;
+-----------+--------------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+-----------+--------------+------+-----+---------+-------+
| id | int(11) | NO | PRI | NULL | |
| title | varchar(50) | NO | | NULL | |
| class | varchar(30) | NO | | NULL | |
| link_url | varchar(100) | NO | | NULL | |
| parent_id | int(11) | NO | | 0 | |
| show | varchar(6) | NO | | NULL | |
+-----------+--------------+------+-----+---------+-------+
6 rows in set (0.00 sec)
我试试这个，但是不行：
$sql = "SELECT * FROM menuSystem ORDER BY id ASC";
$res = mysql_query($sql) or die (mysql_error());
if(mysql_num_rows($res) != 0) {
while($row = mysql_fetch_assoc($res)) {
$id = mysql_real_escape_string ($row['id']);
$title = mysql_real_escape_string ($row['title']);
$class = mysql_real_escape_string ($row['class']);
$link_url = mysql_real_escape_string ($row['link_url']);
$parent_id = mysql_real_escape_string ($row['parent_id']);
$show = mysql_real_escape_string ($row['show']);
$menu = array (
"$id" => array
(
'text' => "$title",
'class' => "$class",
'link' => "$link_url",
'show_condition'=> "$show",
'parent' => "$parent_id"
)
);
}
}
答案 0 :(得分：1)
HI这可能不是您问题的确切答案，但我之前做过类似的事情，所以可能会有所帮助！基本上它是一个基于初始父ID建立站点树的递归循环所以也许你可以看看并稍微修改它
/**
* build_site_tree
*
* @return void
* @author Mike Waites
**/
public function build_site_tree($parent_id)
{
return $this->find_children($parent_id);
}
/** end build_site_tree **/
// -----------------------------------------------------------------------
/**
* find_children
* Recursive loop to find parent=>child relationships
*
* @return array $children
* @author Mike Waites
**/
public function find_children($parent_id)
{
$this->benchmark->mark('find_children_start');
if(!class_exists('Account_model'))
$this->load->model('Account_model');
$children = $this->Account_model->get_children($parent_id);
/** Recursively Loop over the results to build the site tree **/
foreach($children as $key => $child)
{
$childs = $this->find_children($child['id']);
if (count($childs) > 0)
$children[$key]['children'] = $childs;
}
return $children;
$this->benchmark->mark('find_children_end');
}
/** end find_children **/
正如你所看到的那样，只是为了展示这个想法