Question

在使用f字符串打印时如何处理长字符串。我只对字符串的前-后n个感兴趣（特别是在这种情况下，文件的扩展名）。中间部分应替换为3个点。

例如：

代替：

ThisIsMyFilexyz123456s556s54s6afsaf1dshshsb8bbs6s7890.py

ThisIsMyFilexyz12345asaggsvrgahhgbargrarbrvs7890.pdf

ThisIsMyFilexyz12345asa46189sgvs7890.gif

ThisIsMyFilexyz1sgsgbs6rahhgbargrarbrvs7890.jpg

我想要这个：

ThisIsMyFilexy...123.py

ThisIsMyFilexy...456.pdf

ThisIsMyFilexy...789.xml

ThisIsMyFilexy...001.gif

ThisIsMyFilexy...002.py
 
ThisIsMyFilexy...003.py

    import os, arrow
    
    dirname = input("Enter a directory name: ")
    
    def last_modified(filename):
        statinfo = os.stat(filename)
        timestamp = statinfo.st_mtime
        utc = arrow.get(timestamp)
        local = utc.to('Europe/Berlin')
        modified_time = local.format('DD MMMM YYYY HH:mm:ss')
        return modified_time
    
    
    last_time_modified = { filename : last_modified(os.path.join(dirname, filename))
                    for filename in os.listdir(dirname)
                    if os.path.isfile(os.path.join(dirname, filename))}
    
# **here comes the printing part**
    for key, value in last_time_modified.items():
        print(f'{key:<35} {value:>35}')

Answer 1

@Prem Anand和@Vishesh Mangla的结合为我做到了。这是我得到的：

def trunc(arg):
    if len(arg) > 35:
      return arg[:25]+"..."+arg[-10:]
    else:
        return arg

for key, value in last_time_modified.items():
    line_new = '{:<38}  {:>35}'.format(trunc(key), str(value))
    print(line_new)

谢谢你们！

Answer 2

定义一个新函数，该函数可以截断长字符串并以您喜欢的任何格式返回它，并在f字符串中使用该函数

>>> def trunc(s, left=14, right=6, seperator='...'):
...     return s[:left]+seperator+s[-right:]
... 
>>> 
>>> for key in lines:
...     print(f'{trunc(key)}')
... 
ThisIsMyFilexy...890.py
ThisIsMyFilexy...90.pdf
ThisIsMyFilexy...90.gif
ThisIsMyFilexy...90.jpg

使用f字符串在python中处理字符串：处理长字符串

2 个答案: