Pandas DataFrame值转换为列名，列名称转换为值

Question

我有以下 x 数据框：

    a  b  c  d  e  f  g  h
1      1
2         1     2
3   1     2        3     4
4   1     3     2     4   
5   2     4     1     3
6      1        2     4  3

x.to_dict()

{'a': {1: '', 2: '', 3: '1', 4: '1', 5: '2', 6: ''},
 'b': {1: '1', 2: '', 3: '', 4: '', 5: '', 6: '1'},
 'c': {1: '', 2: '1', 3: '2', 4: '3', 5: '4', 6: ''},
 'd': {1: '', 2: '', 3: '', 4: '', 5: '', 6: ''},
 'e': {1: '', 2: '2', 3: '', 4: '2', 5: '1', 6: '2'},
 'f': {1: '', 2: '', 3: '3', 4: '', 5: '', 6: ''},
 'g': {1: '', 2: '', 3: '', 4: '4', 5: '3', 6: '4'},
 'h': {1: '', 2: '', 3: '4', 4: '', 5: '', 6: '3'}}

我想产生此结果（列值表示列名，列名称表示列值，保留行信息）：

    1   2   3   4
1   b
2   c   e
3   a   c   f   h
4   a   e   c   g
5   e   a   g   c
6   b   e   h   g

请注意， x 中的每一行都不能有重复的值

Answer 1

另一种方法：

us-est-2

结果：

d = {'a': {1: '', 2: '', 3: '1', 4: '1', 5: '2', 6: ''},
 'b': {1: '1', 2: '', 3: '', 4: '', 5: '', 6: '1'},
 'c': {1: '', 2: '1', 3: '2', 4: '3', 5: '4', 6: ''},
 'd': {1: '', 2: '', 3: '', 4: '', 5: '', 6: ''},
 'e': {1: '', 2: '2', 3: '', 4: '2', 5: '1', 6: '2'},
 'f': {1: '', 2: '', 3: '3', 4: '', 5: '', 6: ''},
 'g': {1: '', 2: '', 3: '', 4: '4', 5: '3', 6: '4'},
 'h': {1: '', 2: '', 3: '4', 4: '', 5: '', 6: '3'}}

df = pd.DataFrame(d)

df = df.reset_index().melt(id_vars = 'index').query('value!=""')

pd.crosstab(df['index'], df.value, df.variable, aggfunc = 'max')