SerializeObject的当前代码:
dict1={"type":"check"}
dict2={"mac":"00:00:00:00:00:00"}
var json = JsonConvert.SerializeObject(dict1);
var jsonStr = JsonConvert.SerializeObject(dict2);
var arrayOfObjects = JsonConvert.SerializeObject(
new [] { JsonConvert.DeserializeObject(json ), JsonConvert.DeserializeObject(jsonStr) });
它以JSON格式转换数据:
[
{
"type": "CHECK_CONNECTION"
},
{
"mac_address": "00:00:00:00:00"
}
]
我想要
之类的最终输出{
"type":"check",
"mac_address":"00:00:00:00:00:00"
}
答案 0 :(得分:0)
dict1={"type":"check"}
dict2={"mac":"00:00:00:00:00:00"}
var combinedObject = { "type": dict1.type, "mac": dict2.mac };
var jsonCustomObject = JsonConvert.SerializeObject(combinedObject);
请查看这是否可以帮助您。 您试图使用2个元素序列化数组,因此它已反映在序列化的内容中。如果您想要具有2个属性的单个对象的json表示,那么您将创建一个具有2个属性的对象。
答案 1 :(得分:0)
JObject jo = JObject.FromObject(item);
jo.Add("property_name", "property_value");
string json = jo.ToString();
答案 2 :(得分:0)
您必须为数据定义模型。 像这样:
>
import csv
from matplotlib import pyplot as plt
x_axe = []
y_axe = []
with open("file.csv", "r") as csv_file:
csv_reader = csv.DictReader(csv_file)
for lines in csv_reader:
x_axe.append(float(lines[csv_reader.fieldnames[0]]))
with open("file.csv", "r") as csv_file:
csv_reader = csv.DictReader(csv_file)
for i in range(1, len(csv_reader.fieldnames)):
for lines in csv_reader:
y_axe.append(float(lines[csv_reader.fieldnames[i]]))
plt.plot(x_axe, y_axe, label=csv_reader.fieldnames[i])
# y_axe.clear() this did not help
plt.legend()
plt.show()
因此,您可以像这样序列化:
>
//System.ComponentModel.DataAnnotations.Schema
public class Dict
{
[JsonProperty(PropertyName = "type")]
public string Type { get; set; }
[JsonProperty(PropertyName = "mac")]
public string MacAdress { get; set; }
}
请告诉我这是否对您有帮助。