Question

Traceback (most recent call last):
  File "/home/yapjiahong/Coding/python/completed/keyboard/compare.py", line 26, in <module>
    keyboard.write(word_list_PG[random_word])
  File "/usr/local/lib/python3.8/dist-packages/keyboard/__init__.py", line 854, in write
    scan_code, modifiers = next(iter(entries))
StopIteration

如何访问a = [[3, (1, 2, 3, 4, 5)], [3, (5, 4, 3, 2, 1)]] b = [[3, (18, 24, 21, 2, 3)], [3, (3, 4, 76, 7, 8)]]，(1, 2, 3, 4, 5)，(5, 4, 3, 2, 1)和(18, 24, 21, 2, 3)？

我必须在其他列表中搜索此元素。

例如：(3, 4, 76, 7, 8)是否在列表(3, 4, 76, 7, 8)中，如果是，此元素的具体编号是什么？

（在这种情况下[3，（3，4，76，7，8）]）

谢谢。

Answer 1

>>> a = [[3, (1, 2, 3, 4, 5)], [3, (5, 4, 3, 2, 1)]]
>>> b = [[3, (18, 24, 21, 2, 3)], [3, (3, 4, 76, 7, 8)]]
>>> [x for x in a if (3, 4, 76, 7, 8) == x[1]]
[]
>>> [x for x in b if (3, 4, 76, 7, 8) == x[1]]
[[3, (3, 4, 76, 7, 8)]]
>>> [x for x in a + b if (3, 4, 76, 7, 8) == x[1]]
[[3, (3, 4, 76, 7, 8)]]

在元组中搜索组合

1 个答案: