我目前正在处理Python Pygame项目,因为我必须使用JSON文件。我试图读取一个JSON文件,但我无法获取它来打印我想知道的内容。
这是JSON文件
"pokemons": {
"5": {
"name": "Snivy",
"type": "Grass",
"hp": 45,
"attack": 45,
"defence": 55,
"speed": 63,
"moves": [
"Tackle",
"Leer",
"null",
"null"
],
"level": 4,
"xp": 54
},
"2": {
"name": "Tepig",
"type": "Fire",
"hp": 65,
"attack": 63,
"defence": 45,
"speed": 45,
"moves": [
"Tackle",
"Tail Whip",
"Ember",
"null"
],
"level": 7,
"xp": 11
}
}
}
我试图从不同的“ ID”(也称为“ 5”和“ 2”)中读取“名称”,“类型”等,但是我只能从“口袋妖怪”中打印“ 5”和“ 2” “数组
with open("data.json", "r") as f:
data = json.load(f)
for i in data["pokemons"]:
print(i)
答案 0 :(得分:1)
您已将此标题命名为json read from array inside of array python
,但这里没有JSON数组(已转换为Python列表)-您具有JSON对象(已转换为Python字典)。
for i in data["pokemons"]:
data["pokemons"]
是字典,因此像这样遍历它可以为您提供密钥-"5"
和“ 2”`。您可以使用它们来索引数据:
data["pokemons"][i]
这为您提供了代表单个宠物小精灵的对象(字典)之一,您可以从中访问名称:
data["pokemons"][i]["name"]
更好的是,您可以直接遍历data["pokemons"]
的值而不是键:
for pokemon in data["pokemons"].values():
name = pokemon["name"]
或者您可以使用.items()
一次获得两者,例如:
for pid, pokemon in data["pokemons"].items():
# use string formatting to display the pid and matching name together.
print(f"pokemon number {pid} has name {pokemon['name']}")
答案 1 :(得分:1)
我的解决方案
data = '{"pokemons": {"5": {"name": "Snivy","type": "Grass","hp": 45,"attack": 45,"defence": 55,"speed": 63,"moves": ["Tackle","Leer","null","null"],"level": 4,"xp": 54},"2": {"name": "Tepig","type": "Fire","hp": 65,"attack": 63,"defence": 45,"speed": 45,"moves": ["Tackle","Tail Whip","Ember","null"],"level": 7,"xp": 11}}}}'
datadict = json.loads(data)
dataOfId = datadict['pokemons']
for i in dataOfId:
print(dataOfId[i]["name"])
print(dataOfId[i]["type"])