Question

我有一个像这样的数组：

"Turkish 1"
"Indonesian 1"
"Malay 2"
"Indonesian 3"
"Yiddish 1"
"Urdu 2"
"Malay 1"
"Indonesian 2"
"Urdu 1"

我想这样排序：

"Urdu 1"
"Urdu 2"
"Indonesian 1"
"Indonesian 2"
"Indonesian 3"
"Malay 1"
"Malay 2"
"Turkish 1"
"Yiddish 1"

请注意，从“ U”开始的项目在顶部，其余部分按字母顺序排序。如何使用Java或Kotlin中的某种排序算法来实现此目的？

现在，我只知道遍历列表并将项目从U开始放置到列表顶部。

另外，即使在Sqlite中也可以，也请分享。

谢谢。

Answer 1

应用高级排序覆盖的最佳方法是从覆盖条件中得出一个整数值，然后按该值进行排序。

在Java中：

var adBook = (function () {
  // default fields for understanding
  var pplDetails = [{
    firstName: 'Sam',
    lastName: 'Smith',
    phone: '004477995544',
    address: '33 jump st, London'
  }];

  //variables declaration
  var table = $('#table1');
  var $tbody = table.find('tbody');
  var $firstName = table.find('#firstName');
  var $lastName = table.find('#lastName');
  var $phone = table.find('#phone');
  var $address = table.find('#address');
  var $button = table.find('#add');
  var $btnRemove = table.find('#remove');
  var $input = table.find(".edit");


  //events calls
  $button.on('click', adPerson);
  table.on('click', '#remove', delPerson);
  console.log($input);
  build();



  //function to create new table data
  function build() {
    $tbody.html('');
    var length = pplDetails.length;
    for (var i = 0; i < length; i++) {
      table.prepend('<tr><td><input type="text" value="' + pplDetails[i].firstName + '" ></td> <td><input type="text" value="' + pplDetails[i].lastName + '" ></td> <td><input type="text" value="' + pplDetails[i].phone + '" ></td> <td><input type="text" value="' + pplDetails[i].address + '" ></td> <td> <button id="remove" class="btn btn-block">Del</button></td></tr>');
    }
  }

  //function to add persons details
  function adPerson() {
    var data = {
      firstName: $firstName.val(),
      lastName: $lastName.val(),
      phone: $phone.val(),
      address: $address.val()
    };
    pplDetails.push(data);
    $firstName.val('');
    $lastName.val('');
    $phone.val('');
    build()
  }

  //function to delete details
  function delPerson(event) {
    var element = event.target.closest('tr');
    var i = table.find('td').index(element);
    pplDetails.splice(i, 1);
    build();
  }

  return {
    adPerson: adPerson,
    delPerson: delPerson
  };



})();


//Search bar
$(document).ready(function () {
  $("#myInput").on("keyup", function () {
    var value = $(this).val().toLowerCase();
    $('tbody tr').filter(function () {
      $(this).toggle($(this).text().toLowerCase().indexOf(value) > -1)
    });
  });
});

输出

String[] strings = {
        "Turkish 1",
        "Indonesian 1",
        "Malay 2",
        "Indonesian 3",
        "Yiddish 1",
        "Urdu 2",
        "Malay 1",
        "Indonesian 2",
        "Urdu 1" };
Arrays.sort(strings, Comparator.comparingInt((String s) -> s.startsWith("U") ? 0 : 1)
                               .thenComparing(Comparator.naturalOrder()));
System.out.println(Arrays.toString(strings));

在SQL中：

[Urdu 1, Urdu 2, Indonesian 1, Indonesian 2, Indonesian 3, Malay 1, Malay 2, Turkish 1, Yiddish 1]

Answer 2

在Kotlin中，一种方法是将其分为两个列表，对每个列表进行排序，然后将它们加入：

val strings = listOf("Turkish 1", "Indonesian 1", "Malay 2", "Indonesian 3",
                     "Yiddish 1", "Urdu 2", "Malay 1", "Indonesian 2", "Urdu 1")
val result = strings.partition{ it.startsWith("U") }
                    .run{ first.sorted() + second.sorted() }
println(result)

我们可以排序以使特定字母位于顶部并按字母顺序排列吗？

2 个答案: