注意:这与this question不同,因为我需要从另外两个记录中获取数据,而不是从另一个记录中获取两个字段!
MySQL newb。我有两个表,我想从两个表中获取数据,所以我有以下内容:
wp_bowling_fixtures
fixture_id | fixture_date | home_team_id | away_team_id
-----------+--------------+--------------+-------------
1 | 2017-12-12 | 1 | 2
2 | 2017-12-12 | 3 | 4
3 | 2017-12-12 | 5 | 6
4 | 2017-12-12 | 7 | 8
5 | 2017-12-12 | 9 | 10
wp_bowling_teams
team_id | name | division | archived
--------+--------+----------+---------
1 | Team A | 1 | 0
2 | Team B | 1 | 0
3 | Team C | 2 | 1
4 | Team D | 2 | 0
5 | Team E | 3 | 0
6 | Team F | 3 | 0
7 | Team G | 4 | 0
8 | Team H | 4 | 1
9 | Team I | 4 | 0
10 | Team J | 4 | 0
我想要一个SELECT查询产生的结果:
fixture_id | fixture_date | home_team_id | home_team_name | home_team_archived | home_team_division | away_team_id | away_team_name | away_team_archived | away_team_division
-----------+--------------+--------------+----------------+--------------------+--------------------+--------------+----------------+--------------------+-------------------
1 | 2017-12-12 | 1 | Team A | 0 | 1 | 2 | Team B | 0 | 1
我还希望按Fixture_date DESC,home_team_division ASC,home_team_name ASC排序。
希望如此。
TIA,
尼克。
答案 0 :(得分:1)
选择f.fixture_id,f.fixture_date,h.team_id作为home_team_id,h.name作为home_team_name,h.archived作为home_team_archived,h.division作为home_team_division,a.team_id作为away_team_id,a.name作为away_team_name,a。从wp_bowling_fixtures f,wp_bowling_teams h,wp_bowling_teams a,wp_bowling_teams a存档为away_team_archived,a.div分组。 ;
工作。
答案 1 :(得分:0)
sql中的任何操作都不会阻止您两次连接表,但是如果这样做,则必须为它们加别名。
您正在寻找使用
的查询fixtures f
JOIN teams h ON f.home_team_id = h.team_id
JOIN teams a ON f.away_team_id = a.team_id
我给球队h
(代表主队)和a
(代表客队)的别名,这样我就可以区分他们了。尽力填写
答案 2 :(得分:0)
select x.fixture_id, x.fixture_date, x.home_team_id, x.home_team_name, x.home_team_archived, x.home_team_division,
y.away_team_id, y.away_team_name, y.away_team_archived, y.away_team_division from
(select a.fixture_id, a.fixture_date, a.home_team_id, b.name home_team_name, b.archived home_team_archived, b.division home_team_division
from wp_bowling_fixtures a inner join wp_bowling_teams b on A.home_team_id = B.team_id) x
inner join
(select a.fixture_id, a.fixture_date, a.away_team_id, b.name away_team_name, b.archived away_team_archived, b.division away_team_division
from wp_bowling_fixtures a inner join wp_bowling_teams b on A.away_team_id = B.team_id) y on x.fixture_id = y.fixture_id
order by x.fixture_date desc, home_team_division asc, home_team_name asc;`enter code here`