这是我的表格:
<form id="contact-form" method="post">
并且我必须通过单击此按钮将内部数据传递到两个URL:
<button onclick="sendButton();" type="submit" name="submit" class="btn btn-primary btn-lg login-button cont-submit center-block"><i class="fa fa-paper-plane" aria-hidden="true"></i> Send Request</button>
该按钮将触发以下javascript:
function sendButton()
{
document.forms['contact-form'].action='excelReports.php';
document.forms['contact-form'].target='';
document.forms['contact-form'].submit();
document.forms['contact-form'].action='mailAnnual.php';
document.forms['contact-form'].target='';
document.forms['contact-form'].submit();
return true;
}
不幸的是,javascript并没有帮助成功地传递数据,我想知道是否有人知道问题所在。谢谢!
答案 0 :(得分:3)
第二次提交将永远不会执行。您必须使用AJAX。例如:
function sendButton()
{
var form = document.getElementById('contact-form');
var formData = new FormData(form);
var xhr1 = new XMLHttpRequest();
xhr1.open('POST', 'excelReports.php', true);
xhr1.send(formData);
var xhr2 = new XMLHttpRequest();
xhr2.open('POST', 'mailAnnual.php', true);
xhr2.send(formData);
return true;
}