Question

我有两个模型TeamleaderCompany，其中：有很多TeamleaderCompanyTag

TeamleaderCompany

public function teamleaderCompanyTags()
{
    return $this->hasMany('App\TeamleaderCompanyTag');
}

TeamleaderCompanyTag

public function teamleaderCompany()
{
    return $this->belongsTo(TeamleaderCompany::class);
}

当我TeamleaderCompany::all()时，我得到以下结果：

(...)
      "teamleader_company_tags": [
        {
          "id": 7,
          "tag": "hot lead",
          "teamleader_company_id": 3,
          "created_at": "2019-09-03 09:23:51",
          "updated_at": "2019-09-03 09:23:51"
        },
        {
          "id": 8,
          "tag": "reseller",
          "teamleader_company_id": 3,
          "created_at": "2019-09-03 09:23:51",
          "updated_at": "2019-09-03 09:23:51"
        }
      ]
(...)

我想做的是显示TeamleaderCompany的结果，其中teamleaderCompanyTags仅包含一个tag的{{1}}（如果除“转售商”以外还有另一个标签不显示）

'reseller'

谢谢

Answer 1

尝试此查询：

paintings:  [ { type: String} ]

Answer 2

尝试此方法

TeamleaderCompany::with('teamleaderCompanyTags:id,tag')
->whereHas('teamleaderCompanyTags',function(\Illuminate\Database\Eloquent\Builder $query){
                        $query->where('tag', "reseller");
                    })->get();

Answer 3

您有两个条件。

它需要带有“经销商”标签
这是它唯一的标签

TeamleaderCompany::whereHas('teamleaderCompanyTags', function ($query) {
        $query->where('tag', 'reseller');
    })
    ->whereDoesntHave('teamleaderCompanyTags', function ($query) {
        $query->where('tag', '!=', 'reseller');
    })
    ->get()

如何通过关系关系过滤laravel雄辩的结果？

3 个答案: