Question

（1）如果当前作用域中已经存在一个变量，则可以将该值保留为空，而新作用域中的变量将获取当前作用域中的值。

目标是实现语句（1）的示例。

这是尝试：

(Test 1/2) Use "Set Suite Variable" : Set Locally Scoped Variable As Suite Scoped
       [Documentation]     If a variable already exists within the current scope 
       ...                 (i.e. Test 1/2), the value can be left empty and
       ...                 the variable within the new scope (i.e. Test 2/2) gets 
       ...                 the value within the current scope (i.e Test 1/2)

       ${local_to_suite_scoped} =     Set Test Variable   ${3}
       # intentionally not setting any value to comply with the statement (1)
       Set Suite Variable      ${local_to_suite_scoped} 

(Test 2/2) Use "Set Suite Variable" : Use local_to_suite_scoped in this test
       Variable Should Exist   ${local_to_suite_scoped}
       Should Be Equal         ${local_to_suite_scoped}     ${3}  # fails with None != 3, expected 3 == 3

测试2/2失败，但是为什么呢？陈述（1）是否正确或测试用例是否正确实施？如果测试用例的实现不正确，您能否提供正确的实现？

Answer 1

Set Test Variable（如Set Suite Variable -keyword）期望第一个参数是变量的名称。然后，第二个变量将是变量的值。所以代替

${local_to_suite_scoped} =     Set Test Variable   ${3}

做

Set Test Variable    ${local_to_suite_scoped}    ${3}

在http://robotframework.org/robotframework/latest/libraries/BuiltIn.html#Set%20Suite%20Variable上查看更多信息

Robot FW：Buitlin库：设置套件变量：如何将当前测试范围内的变量传递给新的测试范围？

1 个答案: