Question

我正在尝试复制以下while循环，但是两者都交错了我的“卡片”。

这是我当前的while循环，我的目标是重新制作此循环，但反转两个card_force数组的顺序：

while (index >= 0) {

        card_force[index--] = bottom_half[j--];
        card_force[index--] = top_half[i--];
}

这是我想制作的while循环：

while (index >= 0) {
        card_force[index--] = top_half[i--];    
        card_force[index--] = bottom_half[j--];

}

但是，如果两个循环都存在，则原始循环有效，但第二个while循环根本不起作用，从而导致52行返回“ null”。在我需要它退还27卡，1卡，26卡，2卡等等的地方。

似乎很简单的解决方案给我带来了极大的麻烦。

这是我当前的代码：


        String[] card_force = new String[52];
        String[] card_force2 = new String[52];
        int i = top_half.length - 1;
        int j = bottom_half.length - 1;
        int index = 51;


        // Card out shuffle
        while (index >= 0) {

        card_force[index--] = bottom_half[j--];
        card_force[index--] = top_half[i--];  
        }
        // Card in shuffle
        while (index >= 0) {
        card_force2[index--] = top_half[i--];
       card_force2[index--] = bottom_half[j--];
        }


        // Card out shuffle print
        System.out.println("\nCard Shuffle:\n");
        for (String card_force1 : card_force) {
           System.out.println(card_force1);
        }


        // Card in shuffle print
        for (String card_force1 : card_force2) {
           System.out.println(card_force1);
        }


}

代码运行时，将返回以下结果：


Card Shuffle:

Card number 1: King of Clubs
Card number 27: 10 of Spades
Card number 2: Jack of Clubs
Card number 28: King of Diamonds
Card number 3: 6 of Diamonds
Card number 29: 5 of Diamonds
Card number 4: Queen of Hearts
Card number 30: 4 of Hearts
Card number 5: 5 of Clubs
Card number 31: Queen of Diamonds
Card number 6: Ace of Hearts
Card number 32: 7 of Diamonds
Card number 7: 3 of Hearts
Card number 33: 9 of Hearts
Card number 8: 2 of Hearts
Card number 34: 10 of Diamonds
Card number 9: 10 of Clubs
Card number 35: Jack of Diamonds
Card number 10: 2 of Spades
Card number 36: 2 of Diamonds
Card number 11: 9 of Clubs
Card number 37: 2 of Clubs
Card number 12: 8 of Spades
Card number 38: 4 of Spades
Card number 13: 7 of Spades
Card number 39: Ace of Diamonds
Card number 14: 8 of Clubs
Card number 40: 9 of Spades
Card number 15: Jack of Hearts
Card number 41: 6 of Clubs
Card number 16: 3 of Diamonds
Card number 42: 7 of Hearts
Card number 17: 6 of Hearts
Card number 43: King of Hearts
Card number 18: 4 of Clubs
Card number 44: Ace of Clubs
Card number 19: 3 of Spades
Card number 45: 8 of Hearts
Card number 20: Ace of Spades
Card number 46: 5 of Hearts
Card number 21: 10 of Hearts
Card number 47: Jack of Spades
Card number 22: Queen of Clubs
Card number 48: 9 of Diamonds
Card number 23: Queen of Spades
Card number 49: 8 of Diamonds
Card number 24: 7 of Clubs
Card number 50: 5 of Spades
Card number 25: 4 of Diamonds
Card number 51: 6 of Spades
Card number 26: King of Spades
Card number 52: 3 of Clubs
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Answer 1

您需要在第二个循环之前重置index的值。当index为-1时，第一个循环停止，而第二个循环检查该值时，该值仍然相同。结果，第二个循环甚至永远不会运行。

Java阵列算法，将随机播放类型从“ in-shuffle”交换为“ out-shuffle”时出错

1 个答案: