我有一个像下面的pandas DataFrame。
df = pd.DataFrame({'id' : [1,1,1,2,2,3,3,3,3,4,4,5,6,6,6,7,7],
'value' : ["first","second","second","first",
"second","first","third","fourth",
"fifth","second","fifth","first",
"first","second","third","fourth","fifth"]})
我想按[“ id”,“ value”]对此分组,获取每个组的第一行,并使用其值覆盖该组其余行中的值(因此,结果表的尺寸与源表相同)
id value
0 1 first
1 1 second
2 1 second
3 2 second
4 2 first
5 3 first
6 3 third
7 3 fourth
8 3 fifth
9 4 second
10 4 fifth
11 5 first
12 6 first
13 6 second
14 6 third
15 7 fourth
16 7 fifth
预期结果
id value
0 1 first
1 1 first
2 1 first
3 2 second
4 2 second
5 3 first
6 3 first
7 3 first
8 3 first
9 4 second
10 4 second
11 5 first
12 6 first
13 6 first
14 6 first
15 7 fourth
16 7 fourth
我尝试了许多方法,但无济于事...有什么想法吗?
答案 0 :(得分:2)
将GroupBy.transform
与GroupBy.first
一起使用:
df['value'] = df.groupby('id')['value'].transform('first')