Question

我正在尝试比较用户列表中2个元素的相似性以及它们作为整数的给定答案，以百分比与用户给定的输入限制进行比较，如何根据用户输入进行识别，仅在其中分离和比较整数值一会儿循环吗？

这是示例输出

You can check up to 3 pairs

Please provide the first name in the pair (or END to finish) ==> A

Please provide the second name in the pair ==> B

** Sorry! at least one name is not in the data

Another pair? provide the first name (or END to finish) ==> AAAAA

Please provide the second name in the pair ==> AAAAA

TRACE similars 21

** A and B really have a lot in common (>90%)!

Another pair? provide the first name (or END to finish) ==> AAAAA

Please provide the second name in the pair ==> K

TRACE similars 5

** A and K have just few opinions in common (<50%)!
***** Sorry you cannot check more pairs.. you reached the maximum: 5

我的尝试

maxPairs = int(input("What is the maximum number of pairs you want to try? ==> "))
list=[A 1 2, B 4 5,C 6 7]
listofLists=[[A 1 2],[B 4 5],[C 6 7]
firstname=int(input("Please provide the first name in the pair (or END to finish) ==>"))
if firstname!='END':
    secname=int(input("Please provide the first name in the pair (or END to finish) ==>"))
else:
    sys.exit
numP=0
while numP<maxPairs:
    for lst in range (listofLists):
        if firstname=listofLists[lst]:
            pear=item[0]=listofLists[lst]
            itemlist[0]==listofLists
            listst==listoflists[lst[1]]
        if secname=listofLists[lst]:
            pear=item[0]=listofLists[lst]
            itemlist[0]==listofLists
            seclistst==listoflists[lst[1]]
        if lstst=seclistst:
           print(firstname ,"and", secname, "really have a lot in common (>90%)!")
       else:
           print("** Sorry! at least one name is not in the data")
??????
    nump+=1

对于可能因为不清楚或令人困惑而拒绝这篇文章的人，我也不明白，我正在尽力而为。请至少给出您遇到的问题的原因，建议或解决方案。

列表列表中元素之间的While循环比较

0 个答案: