我有一个表(始终按ID升序排列),其中包含5条记录:
ID Sequence
1 1
2 2
3 3
4 4
8 3
9 3
所需的输出是:
ID Sequence
1 1
2 2
3 3
4 6
8 4
9 5
答案 0 :(得分:1)
对我来说,好像有3个直接更新,没什么让它复杂化的了:
module Main exposing (..)
-- Press buttons to increment and decrement a counter.
--
-- Read how it works:
-- https://guide.elm-lang.org/architecture/buttons.html
--
import Browser
import Html exposing (Html, button, div, text, table, tbody, tr, td, input)
import Html.Events exposing (onClick, onInput)
import Html.Attributes exposing (contenteditable)
-- MAIN
main =
Browser.sandbox { init = init, update = update, view = view }
-- MODEL
type alias Model = Int
init : Model
init =
0
-- UPDATE
type Msg
= Increment
| Decrement
update : Msg -> Model -> Model
update msg model =
case msg of
Increment ->
model + 1
Decrement ->
model - 1
testOnInputHandler : String -> Msg
testOnInputHandler str =
let
log = Debug.log "in testOnInputHandler" "here"
in
Increment
-- VIEW
view : Model -> Html Msg
view model =
div []
[ button [ onClick Decrement ] [ text "-" ]
, div [] [ text (String.fromInt model) ]
, button [ onClick Increment ] [ text "+" ]
, table []
[ tbody []
[ tr []
[ td [ contenteditable True, onInput testOnInputHandler] [ text "editable!" ]
]
]
]
, input [ onInput testOnInputHandler ] []
]
答案 1 :(得分:0)
如果您想一步一步做到这一点:
update t
set sequence = v.sequence
from t join
(values (4, 6), (8, 4), (9, 5)
) v(id, sequence)
on t.id = v.id;
如果您必须进行许多此类更新,则分别调用update
会产生额外的开销。