从另一个模型视图将数据插入数据库

时间:2019-11-04 11:47:56

标签: c# asp.net-mvc entity-framework model-view-controller

我的项目有两个模型类,

data.frame

public class BookModel
{
    public Int64 ISBN { get; set; }
    public DateTime AddedDate { get; set; }
    public bool isActive { get; set; }
    public int Quantity { get; set; }
    public int? FormatID { get; set; }
    public virtual FormatModel Format { get; set; }
}

我想在public class FormatModel { public FormatModel() { Books = new HashSet<BookModel>(); } public int ID { get; set; } public string Value { get; set; } public virtual ICollection<BookModel> Books { get; } } 文件中创建一个模态,以在指定格式不存在时添加新格式。

如何为我的模式创建一个“提交”按钮以在Create.cshtml中添加格式?

这是我的观点:

FormatModel

点击“创建格式”按钮后。它为@model RookBookMVC.Models.BookModel @{ ViewBag.Title = "Create"; Layout = "~/Views/Shared/_Layout.cshtml"; ViewBag.ReturnUrl = "/Book/Create"; } <h2>Create</h2> @using (Html.BeginForm("Create", "Book", FormMethod.Post)) { @Html.AntiForgeryToken() <div class="form-horizontal"> <h4>BookModel</h4> <hr /> @Html.ValidationSummary(true, "", new { @class = "text-danger" }) <div class="form-group"> @Html.LabelFor(model => model.FormatID, "FormatID", htmlAttributes: new { @class = "control-label col-md-2" }) <div class="input-group col-md-10"> @Html.DropDownList("FormatID", null, "Select Book Format", htmlAttributes: new { @class = "form-control" }) <div class="input-group-append"> <button type="button" class="btn btn-secondary" data-toggle="modal" data-target="#exampleModalCenter"> Add New </button> </div> </div> @Html.ValidationMessageFor(model => model.FormatID, "", new { @class = "text-danger" }) </div> <div class="form-group"> @Html.LabelFor(model => model.ISBN, htmlAttributes: new { @class = "control-label col-md-2" }) <div class="col-md-10"> @Html.EditorFor(model => model.ISBN, new { htmlAttributes = new { @class = "form-control" } }) @Html.ValidationMessageFor(model => model.ISBN, "", new { @class = "text-danger" }) </div> </div> <div class="form-group"> @Html.LabelFor(model => model.Quantity, htmlAttributes: new { @class = "control-label col-md-2" }) <div class="col-md-10"> @Html.EditorFor(model => model.Quantity, new { htmlAttributes = new { @class = "form-control" } }) @Html.ValidationMessageFor(model => model.Quantity, "", new { @class = "text-danger" }) </div> </div> <div class="form-group"> <div class="col-md-offset-2 col-md-10"> <input type="submit" value="Create" class="btn btn-default" /> </div> </div> </div> } @using (Html.BeginForm("Create", "Format", FormMethod.Post)) { @Html.AntiForgeryToken() <div class="modal fade" id="exampleModalCenter" tabindex="-1" role="dialog" aria-labelledby="exampleModalCenterTitle" aria-hidden="true"> <div class="modal-dialog modal-dialog-centered" role="document"> <div class="modal-content"> <div class="modal-header"> <h5 class="modal-title" id="exampleModalLongTitle">Add New Format</h5> <button type="button" class="close" data-dismiss="modal" aria-label="Close"> <span aria-hidden="true">&times;</span> </button> </div> <div class="modal-body"> <div class="form-group"> @Html.LabelFor(model => model.Format.Value, htmlAttributes: new { @class = "control-label col-md-2" }) <div class="col-md-10"> @Html.EditorFor(model => model.Format.Value, new { htmlAttributes = new { @class = "form-control" } }) @Html.ValidationMessageFor(model => model.Format.Value, "", new { @class = "text-danger" }) </div> </div> </div> <div class="modal-footer"> <button type="button" class="btn btn-secondary" data-dismiss="modal">Close</button> <input type="submit" value="Create Format" class="btn btn-default" /> </div> </div> </div> </div> } <div> @Html.ActionLink("Back to List", "Index") </div> @section Scripts { @Scripts.Render("~/bundles/jqueryval") } 返回false,并且不向我的数据库添加任何数据

如何制作“创建格式”按钮以创建新的格式实体并将其保存在数据库中?

对于其他,我需要通过一个页面创建两个模型

2 个答案:

答案 0 :(得分:0)

您可能必须创建一个视图模型,然后将视图模型属性作为参数传递给“操作-格式/创建帖子”。 ViewModel属性:

public string FormatValue { get; set; }

模式视图:

@Html.EditorFor(model => model.FormatValue, new { htmlAttributes = new { @class = "form-control" } })

参数与从模态形式传递的视图模型属性同名的控制器代码:

[HttpPost]
public ActionResult Create(string formatValue)
{
  using (var dataContext = new YourDbContextModel())
  {
     FormatModel fmtModel = new FormatModel();
     fmtModel.Value = formatValue;
     // rest of your code to save data
  }                   
}

答案 1 :(得分:0)

public class MYViewModel{   public string FormatValue { get; set; } }

Create.cshtml

@model MYViewModel

    <div>
      @Html.EditorFor(model => model.FormatValue, new { htmlAttributes = new { @class = "form-control" } })
    </div>

您的意思是这样吗? 或

 public class MYViewModel{   
  public string FormatValue { get; set; } 
  Public BookModel Book {get; set;}
}