Question

我想弹出一个从数据库中搜索人员的弹出窗口。

仅当我没有输入“ while（$ row = $ sql-> fetch（PDO :: FETCH_ASSOC））”时，才会显示弹出窗口。我已经在没有弹出窗口的其他页面上尝试了相同的代码。它的工作。当我尝试将代码用于弹出窗口时，它不起作用。

<!--Button to open the modal -->
<button class="myBtnSea" id="myBtnSea" data-toggle="modal" data-target="#myModalSea"><i class="fa fa-search"></i></button>

<!-- The Modal -->
<div id="myModalSea" class="modalSea">

    <!-- Modal content -->
    <div class="modalSea-content">
        <span class="closeSea">&times;</span>

        <div id="SearchStaff">
            <h3>Search for Staff</h3>
            <form action="search.php" method="POST">
                <div class="container">
                    <p>You can search either by name or IC number.</p>
                    <hr>

                    <input type="text" name="nama" placeholder="Search By Name" style="text-transform:uppercase"> <br><br>
                    <input type="text" name="icnum" placeholder="Search By IC Number" >

                    <button class="btn" name="search">Search</button><br><br>
                    <!--Table for display the data after search -->
                    <table id="table">
                        <tr>
                            <th>Name</th>
                            <th>Department</th>
                            <th>Campus</th>
                        </tr>
                        <!--This code makes the popup does not appear -->            
                        <?php while ($row = $sql->fetchAll(PDO::FETCH_ASSOC)) { ?>
                            <tr>
                                <td><?php echo $row['name']?></td>
                                <td><?php echo $row['dept']?></td>
                                <td><?php echo $row['campus']?></td>
                            </tr>
                        <?php } ?>
                    </table>
                </div>
            </form>
        </div>
    </div>
</div>

Answer 1

在此处$sql>fetch(PDO::FETCH_ASSOC)循环时，您会遇到语法错误，应该是这样的$sql->fetchAll 使用PDO提取所有记录的正确语法是

while ($row = $sql->fetchAll(PDO::FETCH_ASSOC))

您可以查看有关PDOStatement::fetch

的更多信息

更新：

似乎您没有在按钮中设置数据目标和数据切换

<button class="myBtnSea" id="myBtnSea" data-toggle="modal" data-target="#myModalSea"><i class="fa fa-search"></i></button>

Answer 2

首先，您不能更改引导程序的类别才能使用它。您只能扩展类，否则引导程序将无法工作。我已经更新了整个代码。请尝试。

    <!-- Latest compiled and minified CSS -->
    <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.4.0/css/bootstrap.min.css">

    <!-- jQuery library -->
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>

    <!-- Latest compiled JavaScript -->
    <script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.4.0/js/bootstrap.min.js"></script>

    <!--Button to open the modal -->
    <button class="myBtnSea" id="myBtnSea" data-toggle="modal" data-target="#myModalSea"><i class="fa fa-search"></i> Modal</button>

    <!-- The Modal -->
    <div id="myModalSea" class="modal fade modalSea" role="dialog">
        <div class="modal-dialog">
            <!-- Modal content -->
            <div class="modal-content modalSea-content">
                <div class="modal-header">
                    <span class="close closeSea" data-dismiss="modal">&times;</span>
                </div>
                <div id="SearchStaff">
                    <h3>Search for Staff</h3>
                    <form action="search.php" method="POST">
                        <div class="container">
                            <p>You can search either by name or IC number.</p>
                            <hr>
                            <input type="text" name="nama" placeholder="Search By Name" style="text-transform:uppercase"> <br><br>
                            <input type="text" name="icnum" placeholder="Search By IC Number" >
                            <button class="btn" name="search">Search</button><br><br>
                            <!--Table for display the data after search -->
                            <table id="table">
                                <tr>
                                    <th>Name</th>
                                    <th>Department</th>
                                    <th>Campus</th>
                                </tr>
                                <!--This code makes the popup does not appear -->          
                                <?php while ($row = $sql->fetchAll(PDO::FETCH_ASSOC)) { ?>
                                    <tr>
                                        <td><?php echo $row['name']?></td>
                                        <td><?php echo $row['dept']?></td>
                                        <td><?php echo $row['campus']?></td>
                                    </tr>
                                <?php } ?>
                            </table>
                        </div>
                    </form>
                </div>
            </div>
        </div>
    </div>

第二，您错过了-附近的fetch(PDO::FETCH_ASSOC)连字符。请添加它。

还有一件事情，在循环结果之前，您应该检查查询返回的num行。

模态弹出窗口不出现

2 个答案: