如何将带有逗号的数字字符串转换为整数并将其相加？

时间：2019-09-29 00:21:29

标签： javascript arrays type-conversion

我有一个名为bondFilms的对象，它具有以下属性，例如"title"，"year"和"gross": "272,828,282"。

我想遍历每个项目并添加gross值以获得总gross金额。

const bondFilms = [
{ "title" : "Skyfall", "year" : 2012, "actor" : "Daniel Craig", "gross" : "$1,108,561,008" },
{ "title" : "Thunderball", "year" : 1965, "actor" : "Sean Connery", "gross" : "$1,014,941,117" },
{ "title" : "Goldfinger", "year" : 1964, "actor" : "Sean Connery", "gross" : "$912,257,512" },
{ "title" : "Live and Let Die", "year" : 1973, "actor" : "Roger Moore", "gross" : "$825,110,761" },
{ "title" : "You Only Live Twice", "year" : 1967, "actor" : "Sean Connery", "gross" : "$756,544,419" },
{ "title" : "The Spy Who Loved Me", "year" : 1977, "actor" : "Roger Moore", "gross" : "$692,713,752" },
{ "title" : "Casino Royale", "year" : 2006, "actor" : "Daniel Craig", "gross" : "$669,789,482" },
{ "title" : "Moonraker", "year" : 1979, "actor" : "Roger Moore", "gross" : "$655,872,400" },
{ "title" : "Diamonds Are Forever", "year" : 1971, "actor" : "Sean Connery", "gross" : "$648,514,469" },
{ "title" : "Quantum of Solace", "year" : 2008, "actor" : "Daniel Craig", "gross" : "$622,246,378" },
{ "title" : "From Russia with Love", "year" : 1963, "actor" : "Sean Connery", "gross" : "$576,277,964" },
{ "title" : "Die Another Day", "year" : 2002, "actor" : "Pierce Brosnan", "gross" : "$543,639,638" },
{ "title" : "Goldeneye", "year" : 1995, "actor" : "Pierce Brosnan", "gross" : "$529,548,711" },
{ "title" : "On Her Majesty's Secret Service", "year" : 1969, "actor" : "George Lazenby", "gross" : "$505,899,782" },
{ "title" : "The World is Not Enough", "year" : 1999, "actor" : "Pierce Brosnan", "gross" : "$491,617,153" },
{ "title" : "For Your Eyes Only", "year" : 1981, "actor" : "Roger Moore", "gross" : "$486,468,881" },
{ "title" : "Tomorrow Never Dies", "year" : 1997, "actor" : "Pierce Brosnan", "gross" : "$478,946,402" },
{ "title" : "The Man with the Golden Gun", "year" : 1974, "actor" : "Roger Moore", "gross" : "$448,249,281" },
{ "title" : "Dr. No", "year" : 1962, "actor" : "Sean Connery", "gross" : "$440,759,072" },
{ "title" : "Octopussy", "year" : 1983, "actor" : "Roger Moore", "gross" : "$426,244,352" },
{ "title" : "The Living Daylights", "year" : 1987, "actor" : "Timothy Dalton", "gross" : "$381,088,866" },
{ "title" : "A View to a Kill", "year" : 1985, "actor" : "Roger Moore", "gross" : "$321,172,633" },
{ "title" : "License to Kill", "year" : 1989, "actor" : "Timothy Dalton", "gross" : "$285,157,191" }
];

let result = 0;
bondFilms.forEach((film)=>{
result = result + parseInt(film.gross.replace(",", ""))};
console.log(result);

但是，由于某种原因，我继续得到NaN。我哪里出错了？

6 个答案:

答案 0 :(得分：4)

问题的再现是：

<Typography.Paragraph>

也就是说，我们需要考虑mov rax, 1 mov rdi, 1 mov rsi, [string+3] mov rdx, 3 syscall ，因为console.log(parseInt("$42"));不能。为此，我们可以将正则表达式传递给String#replace："$"，该正则表达式匹配任何文字parseInt或/[$,]/g的字符（我们也可以使用类似"$"的字符，警惕我们可能会意外砍掉主要的负面信号）。请注意","全局标志。

此外，请注意，您缺少/\D/g函数的结尾g。

)

还有更多简洁的方法可以实现归约（将数组转换为单个值），例如Array#reduce，它使用回调函数对数组中的每个元素进行累加，并对数组的初始值进行累加累加器。一元filter运算符给出的结果与Number相同，在没有const bondFilms = [{ "title" : "Skyfall", "year" : 2012, "actor" : "Daniel Craig", "gross" : "$1,108,561,008" },{ "title" : "Thunderball", "year" : 1965, "actor" : "Sean Connery", "gross" : "$1,014,941,117" },{ "title" : "Goldfinger", "year" : 1964, "actor" : "Sean Connery", "gross" : "$912,257,512" },{ "title" : "Live and Let Die", "year" : 1973, "actor" : "Roger Moore", "gross" : "$825,110,761" },{ "title" : "You Only Live Twice", "year" : 1967, "actor" : "Sean Connery", "gross" : "$756,544,419" },{ "title" : "The Spy Who Loved Me", "year" : 1977, "actor" : "Roger Moore", "gross" : "$692,713,752" },{ "title" : "Casino Royale", "year" : 2006, "actor" : "Daniel Craig", "gross" : "$669,789,482" },{ "title" : "Moonraker", "year" : 1979, "actor" : "Roger Moore", "gross" : "$655,872,400" },{ "title" : "Diamonds Are Forever", "year" : 1971, "actor" : "Sean Connery", "gross" : "$648,514,469" },{ "title" : "Quantum of Solace", "year" : 2008, "actor" : "Daniel Craig", "gross" : "$622,246,378" },{ "title" : "From Russia with Love", "year" : 1963, "actor" : "Sean Connery", "gross" : "$576,277,964" },{ "title" : "Die Another Day", "year" : 2002, "actor" : "Pierce Brosnan", "gross" : "$543,639,638" },{ "title" : "Goldeneye", "year" : 1995, "actor" : "Pierce Brosnan", "gross" : "$529,548,711" },{ "title" : "On Her Majesty's Secret Service", "year" : 1969, "actor" : "George Lazenby", "gross" : "$505,899,782" },{ "title" : "The World is Not Enough", "year" : 1999, "actor" : "Pierce Brosnan", "gross" : "$491,617,153" },{ "title" : "For Your Eyes Only", "year" : 1981, "actor" : "Roger Moore", "gross" : "$486,468,881" },{ "title" : "Tomorrow Never Dies", "year" : 1997, "actor" : "Pierce Brosnan", "gross" : "$478,946,402" },{ "title" : "The Man with the Golden Gun", "year" : 1974, "actor" : "Roger Moore", "gross" : "$448,249,281" },{ "title" : "Dr. No", "year" : 1962, "actor" : "Sean Connery", "gross" : "$440,759,072" },{ "title" : "Octopussy", "year" : 1983, "actor" : "Roger Moore", "gross" : "$426,244,352" },{ "title" : "The Living Daylights", "year" : 1987, "actor" : "Timothy Dalton", "gross" : "$381,088,866" },{ "title" : "A View to a Kill", "year" : 1985, "actor" : "Roger Moore", "gross" : "$321,172,633" },{ "title" : "License to Kill", "year" : 1989, "actor" : "Timothy Dalton", "gross" : "$285,157,191" }]; let result = 0; bondFilms.forEach((film) => { result = result + parseInt(film.gross.replace(/[$,]/g, "")) }); console.log(result);的情况下执行转换（结果为can be different，但是在这里不太可能出现边缘情况）。

+

答案 1 :(得分：1)

执行此操作

let result = 0;
bondFilms.forEach((film)=>{
    result = result +  parseInt((film.gross.replace(/[$,]/g, "")});
console.log(result);

答案 2 :(得分：0)

这是.reduce()操作的好例子。

const bondFilms = [
{ "title" : "Skyfall", "year" : 2012, "actor" : "Daniel Craig", "gross" : "$1,108,561,008" },
{ "title" : "Thunderball", "year" : 1965, "actor" : "Sean Connery", "gross" : "$1,014,941,117" },
{ "title" : "Goldfinger", "year" : 1964, "actor" : "Sean Connery", "gross" : "$912,257,512" },
{ "title" : "Live and Let Die", "year" : 1973, "actor" : "Roger Moore", "gross" : "$825,110,761" },
{ "title" : "You Only Live Twice", "year" : 1967, "actor" : "Sean Connery", "gross" : "$756,544,419" },
{ "title" : "The Spy Who Loved Me", "year" : 1977, "actor" : "Roger Moore", "gross" : "$692,713,752" },
{ "title" : "Casino Royale", "year" : 2006, "actor" : "Daniel Craig", "gross" : "$669,789,482" },
{ "title" : "Moonraker", "year" : 1979, "actor" : "Roger Moore", "gross" : "$655,872,400" },
{ "title" : "Diamonds Are Forever", "year" : 1971, "actor" : "Sean Connery", "gross" : "$648,514,469" },
{ "title" : "Quantum of Solace", "year" : 2008, "actor" : "Daniel Craig", "gross" : "$622,246,378" },
{ "title" : "From Russia with Love", "year" : 1963, "actor" : "Sean Connery", "gross" : "$576,277,964" },
{ "title" : "Die Another Day", "year" : 2002, "actor" : "Pierce Brosnan", "gross" : "$543,639,638" },
{ "title" : "Goldeneye", "year" : 1995, "actor" : "Pierce Brosnan", "gross" : "$529,548,711" },
{ "title" : "On Her Majesty's Secret Service", "year" : 1969, "actor" : "George Lazenby", "gross" : "$505,899,782" },
{ "title" : "The World is Not Enough", "year" : 1999, "actor" : "Pierce Brosnan", "gross" : "$491,617,153" },
{ "title" : "For Your Eyes Only", "year" : 1981, "actor" : "Roger Moore", "gross" : "$486,468,881" },
{ "title" : "Tomorrow Never Dies", "year" : 1997, "actor" : "Pierce Brosnan", "gross" : "$478,946,402" },
{ "title" : "The Man with the Golden Gun", "year" : 1974, "actor" : "Roger Moore", "gross" : "$448,249,281" },
{ "title" : "Dr. No", "year" : 1962, "actor" : "Sean Connery", "gross" : "$440,759,072" },
{ "title" : "Octopussy", "year" : 1983, "actor" : "Roger Moore", "gross" : "$426,244,352" },
{ "title" : "The Living Daylights", "year" : 1987, "actor" : "Timothy Dalton", "gross" : "$381,088,866" },
{ "title" : "A View to a Kill", "year" : 1985, "actor" : "Roger Moore", "gross" : "$321,172,633" },
{ "title" : "License to Kill", "year" : 1989, "actor" : "Timothy Dalton", "gross" : "$285,157,191" }
];

let result = bondFilms.reduce((acc, film) =>
  acc + parseFloat(film.gross.slice(1).replace(/,/g, "")), 0
);

console.log(result);

我用.slice()跳过了美元符号，因为已知它的位置是第一个字符。

然后，全局正则表达式删除逗号。

然后将结果解析为浮点数。

答案 3 :(得分：0)

最有效的解决方案是映射对象，然后匹配总值，以便它检测字符串中的数值。

然后使用reduce减少总额。


const bondFilms = [
    { "title" : "Skyfall", "year" : 2012, "actor" : "Daniel Craig", "gross" : "$1,108,561,008" },
    { "title" : "Thunderball", "year" : 1965, "actor" : "Sean Connery", "gross" : "$1,014,941,117" },
    { "title" : "Goldfinger", "year" : 1964, "actor" : "Sean Connery", "gross" : "$912,257,512" },
    { "title" : "Live and Let Die", "year" : 1973, "actor" : "Roger Moore", "gross" : "$825,110,761" },
    { "title" : "You Only Live Twice", "year" : 1967, "actor" : "Sean Connery", "gross" : "$756,544,419" },
    { "title" : "The Spy Who Loved Me", "year" : 1977, "actor" : "Roger Moore", "gross" : "$692,713,752" },
    { "title" : "Casino Royale", "year" : 2006, "actor" : "Daniel Craig", "gross" : "$669,789,482" },
    { "title" : "Moonraker", "year" : 1979, "actor" : "Roger Moore", "gross" : "$655,872,400" },
    { "title" : "Diamonds Are Forever", "year" : 1971, "actor" : "Sean Connery", "gross" : "$648,514,469" },
    { "title" : "Quantum of Solace", "year" : 2008, "actor" : "Daniel Craig", "gross" : "$622,246,378" },
    { "title" : "From Russia with Love", "year" : 1963, "actor" : "Sean Connery", "gross" : "$576,277,964" },
    { "title" : "Die Another Day", "year" : 2002, "actor" : "Pierce Brosnan", "gross" : "$543,639,638" },
    { "title" : "Goldeneye", "year" : 1995, "actor" : "Pierce Brosnan", "gross" : "$529,548,711" },
    { "title" : "On Her Majesty's Secret Service", "year" : 1969, "actor" : "George Lazenby", "gross" : "$505,899,782" },
    { "title" : "The World is Not Enough", "year" : 1999, "actor" : "Pierce Brosnan", "gross" : "$491,617,153" },
    { "title" : "For Your Eyes Only", "year" : 1981, "actor" : "Roger Moore", "gross" : "$486,468,881" },
    { "title" : "Tomorrow Never Dies", "year" : 1997, "actor" : "Pierce Brosnan", "gross" : "$478,946,402" },
    { "title" : "The Man with the Golden Gun", "year" : 1974, "actor" : "Roger Moore", "gross" : "$448,249,281" },
    { "title" : "Dr. No", "year" : 1962, "actor" : "Sean Connery", "gross" : "$440,759,072" },
    { "title" : "Octopussy", "year" : 1983, "actor" : "Roger Moore", "gross" : "$426,244,352" },
    { "title" : "The Living Daylights", "year" : 1987, "actor" : "Timothy Dalton", "gross" : "$381,088,866" },
    { "title" : "A View to a Kill", "year" : 1985, "actor" : "Roger Moore", "gross" : "$321,172,633" },
    { "title" : "License to Kill", "year" : 1989, "actor" : "Timothy Dalton", "gross" : "$285,157,191" }
]

const xs = bondFilms.map(x =>{
    return parseInt(x.gross.replace(',' , '').match(/\d+/g , 10))    
});

const total = xs.reduce((x , y) =>{
    return x + y;
});

console.log(total)

答案 4 :(得分：0)

基于Sagar提取数字值的答案，这是使用Array.reduce在一行中完成此操作的方法：

const total = bondFilms.reduce( (prev, current) => (prev + parseInt(current.gross.replace(",", "").replace("$", ""))), 0);

答案 5 :(得分：0)

我尝试了这个，似乎可行。

var result = 0;
for(i=0; i<bondFilms.length; i++){ 
result = result +Number(bondFilms[i].gross.replace("$", "").replace(/,/g,'')) 
};
console.log(result);
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