Question

我想知道是否有可能基于用户选择的值来获取全局变量名称。例如，在游戏菜单中，如果用户选择值1，则显示“ START”（START是全局变量的名称）

我已经使用if-elif了，因为我的菜单不是很大，但是有没有更系统的方法？

print("The MENU")

print("Choose from the following:\n"
      "1 - SEARCH A CONTACT\n"
      "2 - ADD A CONTACT\n"
      "3 - CHANGE A CONTACT\n"
      "4 - DELETE A CONTACT\n"
      "5 - DISPLAY CONTACTS\n"
      "0 - Quit")

choice = int(input("Variant: "))
while choice not in [SEARCH_CONTACT, ADD_CONTACT, CHANGE_CONTACT, DELETE_CONTACT, DISPLAY_CONTACTS, QUIT]:
    print("Not available, please select only from [0, 1, 2, 3, 4, 5]!")
    choice = int(input("Your choice: "))
if choice == SEARCH_CONTACT:
    print("You want to search a contact!")
elif choice == ADD_CONTACT:
    print('You want to add a contact!')
elif choice == CHANGE_CONTACT:
    print("You want to change a contact!")
elif choice == DELETE_CONTACT:
    print('You want to delete a contact!')
elif choice == DISPLAY_CONTACTS:
    print('You want to display the contacts!')
else:
    print("QUITTING...")

除了一堆长长的代码，还有没有办法使用循环和仅一个print语句？全局变量的名称将更改为更精确的名称

Answer 1

您不想直接这样做（Can I print original variable's name in Python?）

要做到要实现的目标的pythonic方法是使用字典（https://www.w3schools.com/python/python_dictionaries.asp）。

就是这样：

dictchoices =   {
0: "NOTHING",
1: "SEARCH A CONTACT",
2: "ADD A CONTACT"
}

choice = int(input("Variant: "))

print("You want to ", dictchoice[choice], "!")

您还可以创建包含完整句子的另一本词典，以便仅从该词典中进行打印：

dictchoices2 =  {
0: "You don't want to do anything. Too bad!",
1: "You want to search a contact. Be careful, contacts are scary.",
2: "You want to add a contact. Would that fill your existential void?"
}

choice = int(input("Variant: "))

print(dictchoice2[choice])

根据值获取局部变量名称

1 个答案: