Question

Laravel版本：5.8 Adldap2-Laravel版本：6.0 PHP版本：7.1.3 LDAP类型：ActiveDirectory

您好，凭据是正确的，但我无法通过其登录。 Adlap :: auth（）-> attempt（）始终返回false。

$user_format = env('LDAP_USER_FORMAT', 'cn=%s,dc=corp,dc=org');
$userdn = sprintf($user_format, $username);

 if(Adldap::auth()->attempt($userdn, $request->password , true)) {
           return redirect('/home');
 } else {
            dd($userdn);
 }

config / ldap_auth.php

'connection' => env('LDAP_CONNECTION', 'default'),
'provider' => Adldap\Laravel\Auth\DatabaseUserProvider::class,
'model' => App\User::class,
'rules' => [
    Adldap\Laravel\Validation\Rules\DenyTrashed::class,
],
'identifiers' => [
    'ldap' => [
        'locate_users_by' => 'userprincipalname',
        'bind_users_by' => 'distinguishedname',
    ],

    'database' => [
        'username_column' => 'username',
    ],

    'windows' => [
        'locate_users_by' => 'samaccountname'
    ],
],
'login_fallback' => env('LDAP_LOGIN_FALLBACK', false),
'usernames' => [
    'ldap' => 'userprincipalname', // was just 'userprincipalname'
    'eloquent' => 'username', // was 'email'
],
'sync_attributes' => [
    'username' => 'userprincipalname',
    'name' => 'cn',
],

'logging' => [
    'enabled' => env('LDAP_LOGGING', true),

Answer 1

我解决了。

用户名格式错误。我不需要这些信息。

$user_format = env('LDAP_USER_FORMAT', 'cn=%s,dc=corp,dc=org');
$userdn = sprintf($user_format, $username);

 if(Adldap::auth()->attempt($userdn, $request->password , true)) {

现在，我以表格形式输入值。就我而言，name.surname


if(Adldap::auth()->attempt($request->username, $request->password , true)) {

Adldap :: auth（）-> attempt（用户名，密码）始终返回false

1 个答案: