Question

我有下表：

NO  ACTION_DT           REQUEST_TYPE STATUS_CD  
34  12/5/2007 6:57:04 PM    CREATE  APPROVED    
34  1/10/2012 2:53:49 PM    DELETE  PENDING 
34  1/10/2012 3:00:00 PM    DELETE  DENIED  
34  1/7/2013 9:42:33 AM     DELETE  APPROVED

我想根据条件创建一个start_dt。

我需要状态代码为“已批准”或“已拒绝”后的request_start_date的第一个值

“已批准”或“已拒绝”表示请求结束。接下来的行应具有第一行action_dt，直到满足批准或拒绝的条件。

预期输出：

NO  ACTION_DT               REQUEST_TYPE    STATUS_CD   REQUEST_START_DT
34  12/5/2007 6:57:04 PM    CREATE          APPROVED    12/5/2007 6:57:04 PM    
34  1/10/2012 2:53:49 PM    DELETE          PENDING     1/10/2012 2:53:49 PM  
34  1/10/2012 3:00:00 PM    DELETE          DENIED      1/10/2012 2:53:49 
34  1/7/2013 9:42:33 AM     DELETE          APPROVED    1/7/2013 9:42:33 AM

代码：

select *,
CASE
WHEN W.REQUEST_TYPE IN ('CREATE','UPDATE','RELEASE','DELETE','HOLD') AND    W.STATUS_CD IN ('NEW') THEN W.ACTION_DT
WHEN W.REQUEST_TYPE IN ('CREATE','UPDATE','RELEASE','DELETE','HOLD') AND W.STATUS_CD IN ('PENDING','NEW','DENIED','APPROVED')  AND LAG(W.ACTION_USER)   OVER (PARTITION BY W.NO ORDER BY W.ACTION_DT) IS NULL THEN W.ACTION_DT
--WHEN W.REQUEST_TYPE IN ('CREATE','UPDATE','RELEASE','DELETE','HOLD') AND W.STATUS_CD NOT IN ('NEW') THEN (CASE WHEN W.STATUS_CD IN ('APPROVED','DENIED')   THEN LAG(W.ACTION_DT) 
--OVER (PARTITION BY W.NO,W.REQUEST_TYPE ORDER BY W.ACTION_DT)END)
 WHEN LAG(W.STATUS_CD) OVER (PARTITION BY W.NO ORDER BY W.ACTION_DT)

  /*WHEN W.REQUEST_TYPE IN ('CREATE','UPDATE','RELEASE','DELETE','HOLD') AND W.STATUS_CD NOT IN ('NEW') THEN LAG(CASE WHEN W.STATUS_CD IN ('APPROVED','DENIED') THEN W.ACTION_DT END )
  --,ROWS BETWEEN UNBOUNDED PRECEDING AND PRECEDING )
 OVER (PARTITION BY W.NO ORDER BY W.ACTION_DT) */

  ELSE NULL
--ELSE W.ACTION_DT
  END REQUEST_START_DT
  from w

Answer 1

Oracle设置：

CREATE TABLE W ( NO, ACTION_DT, REQUEST_TYPE, STATUS_CD ) AS
SELECT 34, DATE '2007-12-05' + INTERVAL '18:57:04' HOUR TO SECOND, 'CREATE', 'APPROVED' FROM DUAL UNION ALL
SELECT 34, DATE '2012-01-10' + INTERVAL '14:53:49' HOUR TO SECOND, 'DELETE', 'PENDING'  FROM DUAL UNION ALL
SELECT 34, DATE '2012-01-10' + INTERVAL '15:00:00' HOUR TO SECOND, 'DELETE', 'DENIED'   FROM DUAL UNION ALL
SELECT 34, DATE '2013-01-07' + INTERVAL '09:42:33' HOUR TO SECOND, 'DELETE', 'APPROVED' FROM DUAL

查询：

使用COUNT分析函数获得APPROVED或DENIED行数的累积计数，从而为您提供一些按以下方式对行进行分组的方法：

SELECT W.*,
       COUNT( CASE WHEN STATUS_CD IN ( 'APPROVED', 'DENIED' ) THEN 1 END )
         OVER ( PARTITION BY NO ORDER BY ACTION_DT )
         + CASE WHEN STATUS_CD IN ( 'APPROVED', 'DENIED' ) THEN 0 ELSE 1 END
         AS grp
FROM   w

哪个输出：

NO | ACTION_DT           | REQUEST_TYPE | STATUS_CD | GRP
-: | :------------------ | :----------- | :-------- | --:
34 | 2007-12-05 18:57:04 | CREATE       | APPROVED  |   1
34 | 2012-01-10 14:53:49 | DELETE       | PENDING   |   2
34 | 2012-01-10 15:00:00 | DELETE       | DENIED    |   2
34 | 2013-01-07 09:42:33 | DELETE       | APPROVED  |   3

然后，您可以使用它找到每个组的最低ACTION_DT：

SELECT no,
       action_dt,
       request_type,
       status_cd,
       MIN( action_dt ) OVER ( PARTITION BY no, grp ) AS request_start_dt
FROM   (
  SELECT W.*,
         COUNT( CASE WHEN STATUS_CD IN ( 'APPROVED', 'DENIED' ) THEN 1 END )
           OVER ( PARTITION BY NO ORDER BY ACTION_DT )
           + CASE WHEN STATUS_CD IN ( 'APPROVED', 'DENIED' ) THEN 0 ELSE 1 END
           AS grp
  FROM   w
)
ORDER BY action_dt

输出：

NO | ACTION_DT           | REQUEST_TYPE | STATUS_CD | REQUEST_START_DT   
-: | :------------------ | :----------- | :-------- | :------------------
34 | 2007-12-05 18:57:04 | CREATE       | APPROVED  | 2007-12-05 18:57:04
34 | 2012-01-10 14:53:49 | DELETE       | PENDING   | 2012-01-10 14:53:49
34 | 2012-01-10 15:00:00 | DELETE       | DENIED    | 2012-01-10 14:53:49
34 | 2013-01-07 09:42:33 | DELETE       | APPROVED  | 2013-01-07 09:42:33

db <>提琴here

查找每组动作的开始时间

1 个答案: