我想使用计时器自动移动按钮,并希望在按下另一个键时改变方向,就像在蛇中发生的一样
我使用了一个字符串来设置方向,但这是行不通的。
string x =“ right”;
public Form1()
{
InitializeComponent();
timer1.Interval = 1000;
timer1.Start();
}
private void Player_KeyDown(object sender, KeyEventArgs e)
{
if (e.KeyCode == Keys.W)
{
string x = "up";
}
else if (e.KeyCode == Keys.S)
{
string x = "down";
}
else if (e.KeyCode == Keys.D)
{
string x = "right";
}
else if (e.KeyCode == Keys.A)
{
string x = "left";
}
}
private void Form1_Load(object sender, EventArgs e)
{
}
private void Timer1_Tick(object sender, EventArgs e)
{
while (x == "up")
{
Player.Top -= 10;
}
while (x == "down")
{
Player.Top += 10;
}
while (x == "right")
{
Player.Left += 10;
}
while (x == "left")
{
Player.Left -= 10;
}
}
}
按钮只是消失了,但是我希望它移动十个直到它被按下,例如“ D”,然后它改变方向
答案 0 :(得分:1)
1:您每次在player_keyDown事件中均在本地创建变量'x'时,请全局创建该变量。
2:您正在使用while循环,不需要,因为您已经在使用timer_tick。
3:代替顶部,左侧使用按钮的Location属性,它为您提供X,Y坐标
public partial class Form2 : Form
{
public Form2()
{
InitializeComponent();
timer1.Interval = 1000;
timer1.Start();
}
string x = "right";
private void Player_KeyDown(object sender, KeyEventArgs e)
{
if (e.KeyCode == Keys.W)
{
x = "up";
}
else if (e.KeyCode == Keys.S)
{
x = "down";
}
else if (e.KeyCode == Keys.D)
{
x = "right";
}
else if (e.KeyCode == Keys.A)
{
x = "left";
}
}
private void timer1_Tick(object sender, EventArgs e)
{
if (x == "up")
{
Player.Location = new System.Drawing.Point(Player.Location.X, Player.Location.Y - 10);
}
if (x == "down")
{
Player.Location = new System.Drawing.Point(Player.Location.X, Player.Location.Y + 10);
}
if (x == "right")
{
Player.Location = new System.Drawing.Point(Player.Location.X + 10, Player.Location.Y);
}
if (x == "left")
{
Player.Location = new System.Drawing.Point(Player.Location.X - 10, Player.Location.Y);
}
}
}