将字符串拆分成JavaScript中的单词

Question

我必须在JavaScript中将字符串拆分成一个单词。

var urlCurrent = "www.example.com/web/americas/home";
var siteNames = ["americas","international","europe","asia-pacific","africa-middle-east","russia","india"];
var siteNamesJoin = siteNames.join('|');
var siteUrlCurrent = urlCurrent.split(siteNamesJoin);

在这里，我必须使用数组中的单词来拆分urlCurrent字符串。因此最后我必须得到www.example.com/web/americas。我没有得到正则表达式。

Answer 1

您可以使用

new RegExp("^.*?(?:" + siteNamesJoin + "|$)")

图案看起来像

^.*?(?:americas|international|europe|asia-pacific|africa-middle-east|russia|india|$)

请参见regex graph：

详细信息

• ^-字符串的开头
• .*?-除换行符以外的任何0个或多个字符，应尽可能少
• (?:americas|international|europe|asia-pacific|africa-middle-east|russia|india|$)-管道之间或字符串结尾之间的任何值。

请参阅JS演示

var urlCurrent = "www.example.com/web/americas/home";
var siteNames = ["americas","international","europe","asia-pacific","africa-middle-east","russia","india"];
var siteNamesJoin = siteNames.join('|');
var match = urlCurrent.match(new RegExp("^.*?(?:" + siteNamesJoin + "|$)"));
var siteUrlCurrent = match ? match[0] : "";
console.log(siteUrlCurrent);

注意：如果siteNames“单词”可能包含特殊的正则表达式元字符，则需要转义siteNames项：

var siteNamesJoin = siteNames.map(function (x) { return x.replace(/[-\/\\^$*+?.()|[\]{}]/g, '\\$&') }).join('|');

此外，如果这些单词必须在/或字符串结尾之间匹配，则可以调整模式：

var match = urlCurrent.match(new RegExp("^(.*?)/(?:(?:" + siteNamesJoin + ")(?![^/])|$)"));

查看另一个演示。

var urlCurrent = "www.example.com/web/americas/home";
var siteNames = ["americas","international","europe","asia-pacific","africa-middle-east","russia","india"];
var siteNamesJoin = siteNames.map(function (x) { return x.replace(/[-\/\\^$*+?.()|[\]{}]/g, '\\$&') }).join('|');
var match = urlCurrent.match(new RegExp("^.*?/(?:(?:" + siteNamesJoin + ")(?![^/])|$)"));
var siteUrlCurrent = match ? match[0] : "";
console.log(siteUrlCurrent);

Answer 2

也许这对您有帮助，我想您不需要正则表达式：

var urlCurrent = "www.example.com/web/americas/home";
var siteNames = ["americas","international","europe","asia-pacific","africa-middle-east","russia","india"];
var siteNamesJoin = siteNames.join('|');
var siteUrlCurrent = urlCurrent.split(siteNamesJoin);

const pos = urlCurrent.split("/")[2];
let url;

for(const index in siteNames) {
  if(pos === siteNames[index]) {
     url = urlCurrent.substring(0,urlCurrent.lastIndexOf("/"));
  }
}

console.log(url);

Answer 3

使用正则表达式和匹配项

   Memberid Question Numeric Answers FreeText Answers
0         1       Q1               3                 
1         1       Q2               2                 
2         1       Q3                        Test Text
3         2       Q1               3                 
4         2       Q2               2                 
5         2       Q3                        Test Text