我在数据路径上使用read.csv。它返回一个数据帧。我希望能够在此数据框中获得单个值,但我却获得了显示水平的值列表。
我尝试了几种方法来获取所需的值。在下一部分中,我将向您展示我的尝试和获得的结果。
这是我的简单数据框:
"OGM","Nutrient","data3"
"tomato","iron",0.03
"domestic cat","iron",0.02
"zebrafish","zing",0.02
"giraffe","nitrate", 0.09
"common cougar","manganese",0.05
"fawn","nitrogen",0.04
"daim","bromure",0.08
"wild cat","iron",0.05
"domestic cat","calcium",0.02
"muren","calcium",0.07
"jaguar","iron",0.02
"green turtle","sodium",0.01
"dave grohl","metal",0.09
"zebra","nitrates",0.12
"tortoise","sodium",0.16
"dinosaur","calcium",0.08
"apex mellifera","sodium",0.15
这是我加载数据的方式:
#use read.csv on the datapath contained in file
fileData <- read.csv(file[4][[1]])
print(fileData[1][1])
我想要的是访问一个值:例如,“ tomato”或“ nitrate”。我想要的结果就是这样:
>[1] tomato
这是我尝试过的,得到的结果:
print(fileData[1][1])
返回
> OGM
>1 tomato
>2 domestic cat
>3 zebrafish
>4 giraffe...
print(fileData$OGM[1])
返回
> [1] tomato
Levels: apex mellifera common cougar daim...
print(fileData[1][[1]])
返回
> [1] tomato domestic cat zebrafish giraffe common cougar [...]
[15] tortoise dinosaur apex mellifera
Levels: apex mellifera common cougar daim...
print(fileData$OGM[[1]])
返回
Levels: apex mellifera common cougar daim...
为这个愚蠢的问题表示歉意,但我有点迷茫。感谢所有帮助。如果要我编辑帖子以使其更清晰,请告诉我。谢谢。
答案 0 :(得分:1)
一些建议
尝试使用readr::read_csv
而不是read.csv
来读取数据。这将解决stringsAsFactors问题。或使用Stewart Macdonald建议的方法。
一旦有了数据,就可以按以下方式操作
# Make a sample dataframe
library(tidyverse)
df <- tribble(~OGM, ~Nutrient, ~data3,
"tomato","iron",0.03,
"domestic cat","iron",0.02,
"zebrafish","zing",0.02,
"giraffe","nitrate", 0.09,
"common cougar","manganese",0.05,
"fawn","nitrogen",0.04,
"daim","bromure",0.08,
"wild cat","iron",0.05,
"domestic cat","calcium",0.02,
"muren","calcium",0.07,
"jaguar","iron",0.02,
"green turtle","sodium",0.01,
"dave grohl","metal",0.09,
"zebra","nitrates",0.12,
"tortoise","sodium",0.16,
"dinosaur","calcium",0.08,
"apex mellifera","sodium",0.15)
df %>%
select(OGM) %>% # select the OGM column
filter(OGM == 'tomato') %>%
pull # convert to a vector
[1] "tomato"