比较shell中的两个变量

时间:2011-04-14 03:30:13

标签: linux shell scripting

我有两个变量 $ a和$ b

$a=Source/dir1/dir11
$b=Destination/dir1/dir11

$ a和$ b更改但是缩写Source /和Destination /保持不变 我想比较$ a和$ b没有Source /和Destination /

我应该怎么做? 以下代码我正在使用

   SOURCE_DIR_LIST=`find Source/ -type d`
   DEST_DIR_LIST=`find Destination/ -type d`

for dir_s in $SOURCE_DIR_LIST
do
    for dir_d in $DEST_DIR_LIST
    do

        if [ ${dir_s/Source\//''} == ${dir_d/Destination\//''} ]
        then
                echo " path match = ${dir_s/Source\//''}"

        else
             echo "path does not match source path = ${dir_s/Source\//''} "
             echo " and destination path= ${dir_d/Destination\//''} "
        fi
    done
done

但输出如下:

 path match = ''
./compare.sh: line 9: [: ==: unary operator expected
path does not match source path = ''
 and destination path= ''dir2
./compare.sh: line 9: [: ==: unary operator expected
more

4 个答案:

答案 0 :(得分:4)

if [ ${a/Source/''} == ${b/Destination/''} ]
then
  # do your job
fi

答案 1 :(得分:1)

if [ `echo $a | sed 's/Source\///'` == `echo $b | sed 's/Destination\///'` ]
then
    # Do something
fi

答案 2 :(得分:1)

使用case/esac

case "${a#*/}" in
 ${b#*/} ) echo "ok";;
esac

答案 3 :(得分:0)

或使用awk

 #!/bin/bash
    a="Source/dir1/dir11"
    b="Destination/dir1/dir11"
    SAVEIFS=$IFS
    IFS="\/"
    basea=$(echo $a | awk '{print $1}')
    baseb=$(echo $b | awk '{print $1}') 
    if [ $basea == $baseb ]; then
        echo "Equal strings"
    fi
    IFS=$SAVEIFS