我不熟悉Thymeleaf,并试图在Themeleaf模板上创建动态表。
我该怎么办.. ??
我一直在搜寻,但没有得到适当的答案。问题是我无法迭代List
<tr class="headings">
<th class="column-title">ID</th>
<th class="column-title">Name</th>
<th class="column-title">Salary</th>
<th class="column-title">Status</th>
</tr>
</thead>
<tbody>
<tr class="even pointer" th:each="row:${rows}" id = "tablerow">
<td class=" " th:text="${row.getId()}">Id</td>
<td class=" " th:text="${row.getName()}">Name</td>
<td class=" " th:utext="${row.getSalary()}">Salary</td>
<td class=" " th:text="${row.getStatus()}">Active</td>
</tr>
</tbody>
我需要动态设置值,因为结果查询会不断变化。现在,列名已经过硬编码,并且值也通过 row.getId 得到了。如果没有ID,那行中应该有什么用呢?示例行。 行获得为List
谢谢。
答案 0 :(得分:0)
您可以像Map
一样轻松地遍历List
。最简单的形式是:
<tbody>
<tr class="even pointer" th:each="row: ${rows}" id="tablerow">
<td th:each="field: ${row}" th:text="${field.value}" />
</tr>
</tbody>
但是,由于Maps
没有特定的顺序(除非您使用的是TreeMap
之类的东西),所以我这样做的方式将是这样的(完整示例应匹配您的示例表):
控制器
List<String> headers = Arrays.asList("ID", "Name", "Salary", "Status");
List<Map<String, Object>> rows = new ArrayList<>();
rows.add(Map.of("ID", "1", "Name", "Jim", "Salary", "50000", "Status", "active"));
rows.add(Map.of("ID", "2", "Name", "Sally", "Salary", "50000", "Status", "inactive"));
模板
<table>
<thead>
<tr class="headings">
<th th:each="header: ${headers}" class="column-title" th:text="${header}" />
</tr>
</thead>
<tbody>
<tr class="even pointer" th:each="row: ${rows}" id="tablerow">
<td th:each="header: ${headers}" th:text="${row.get(header)}" />
</tr>
</tbody>
</table>
哪个会产生:
<table>
<thead>
<tr class="headings">
<th class="column-title" >ID</th>
<th class="column-title" >Name</th>
<th class="column-title" >Salary</th>
<th class="column-title" >Status</th>
</tr>
</thead>
<tbody>
<tr class="even pointer" id="tablerow">
<td >1</td>
<td >Jim</td>
<td >50000</td>
<td >active</td>
</tr>
<tr class="even pointer" id="tablerow">
<td >2</td>
<td >Sally</td>
<td >50000</td>
<td >inactive</td>
</tr>
</tbody>
</table>