我在查询数据以及ES中的嵌套对象时遇到了一些麻烦。 更像是SQL中的左联接,
SELECT
select_list
FROM
T1
LEFT JOIN T2 ON
join_predicate;
将根据给定的术语和匹配的嵌套对象返回所有数据。
请参见以下示例。
1。。这是我的映射...
{
mappings: {
_doc: {
properties: {
accountId: { type: 'keyword' },
history: {
type: 'nested',
properties: {
status: { type: 'keyword' },
createdAt: { type: 'date' }
}
}
}
}
}
}
2。 ES内部的数据
[
{
accountId: 10001,
history: {
status: "NEW",
createdAt: "2010-01-01"
}
},
{
accountId: 10002,
history: {
status: "NEW",
createdAt: "2010-01-02"
}
},
{
accountId: 10001,
history: {
status: "FAIL",
createdAt: "2010-01-03"
}
},
{
accountId: 10004,
history: {
status: "FAIL",
createdAt: "2010-01-04"
}
},
{
accountId: 10001,
history: {}
},
{
accountId: 10001
}
]
3。。我需要获取accountId为10001的所有数据(包括嵌套对象)。
所以基本上它应该返回下面的数据。
[
{
accountId: 10001,
history: {
status: "NEW",
createdAt: "2010-01-01"
}
},
{
accountId: 10001,
history: {
status: "FAIL",
createdAt: "2010-01-03"
}
},
{
accountId: 10001,
history: {}
},
{
accountId: 10001
}
]
你能帮我吗?
答案 0 :(得分:2)
看到您只需要包含"accountId":"10001"
的文档,您只需要使用一个简单的Term Query就可以了:
POST <your_index_name>/_search
{
"query": {
"bool": {
"must": [
{
"term": {
"accountId": {
"value": "10001"
}
}
}
]
}
}
}
您的回复将在您提取原始文档时返回它。
{
"took" : 1,
"timed_out" : false,
"_shards" : {
"total" : 1,
"successful" : 1,
"skipped" : 0,
"failed" : 0
},
"hits" : {
"total" : {
"value" : 4,
"relation" : "eq"
},
"max_score" : 0.44183275,
"hits" : [
{
"_index" : "somenested",
"_type" : "_doc",
"_id" : "1",
"_score" : 0.44183275,
"_source" : {
"accountId" : "10001",
"history" : {
"status" : "NEW", <--- Doc 1
"createdAt" : "2010-01-01"
}
}
},
{
"_index" : "somenested",
"_type" : "_doc",
"_id" : "3",
"_score" : 0.44183275,
"_source" : {
"accountId" : "10001", <--- Doc 2
"history" : {
"status" : "FAIL",
"createdAt" : "2010-01-03"
}
}
},
{
"_index" : "somenested",
"_type" : "_doc",
"_id" : "5",
"_score" : 0.44183275,
"_source" : {
"accountId" : "10001", <--- Doc 3
"history" : { }
}
},
{
"_index" : "somenested",
"_type" : "_doc",
"_id" : "6",
"_score" : 0.44183275,
"_source" : {
"accountId" : "10001" <--- Doc 4
}
}
]
}
}
希望这会有所帮助!