如何在Criteria API / JPQL中使用具有一对多属性的JPA投影

时间:2019-05-28 11:03:15

标签: java hibernate spring-data-jpa jpql criteria-api

我很难使用Criteria API 创建查询,该查询可投影查询实体的属性并实例化DTO。其中一个投影属性会与另一个实体建立一对多关系,因此它是一组相关实体。我正在使用访存联接来检索集合。但是我收到以下错误:

org.hibernate.QueryException: query specified join fetching, but the owner of the fetched association was not present in the select list

我已经尝试过使用常规联接,但是在这种情况下,不会填充相关实体集。完全删除联接和/或获取也无济于事。

我正在使用JPA规范2.0,Hibernate 4.2.21,最终版本,Spring Data JPA 1.10.11.RELEASE。

有人可以建议我吗?我也很高兴JPQL可以正常工作。

这是我对查询的实现:

@Override
public List<EntityADto> findByPartialKey1OrderByPartialKey2(String partialKey1) {
    // Create query
    final CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder();
    final CriteriaQuery<EntityADto> criteriaQuery = criteriaBuilder.createQuery(EntityADto.class);

    // Define FROM clause
    final Root<EntityA> root = criteriaQuery.from(EntityA.class);
    root.fetch(EntityA_.oneToManyAttribute);

    // Define DTO projection
    criteriaQuery
            .select(criteriaBuilder.construct(
                    EntityADto.class,
                    root.get(EntityA_.id).get(EntityAId_.partialKey1),
                    root.get(EntityA_.id).get(EntityAId_.partialKey2),
                    root.get(EntityA_.stringAttribute1),
                    root.get(EntityA_.stringAttribute2),
                    root.get(EntityA_.oneToManyAttribute)))
            .orderBy(criteriaBuilder.asc(root.get(EntityA_.id).get(EntityAId_.partialKey2)))
            .distinct(true);

    // Define WHERE clause
    final ParameterExpression<String> parameterPartialKey1 = criteriaBuilder.parameter(String.class);
    criteriaQuery.where(criteriaBuilder.equal(root.get(EntityA_.id).get(EntityAId_.partialKey1), parameterPartialKey1));

    // Execute query
    final TypedQuery<EntityADto> typedQuery = entityManager.createQuery(criteriaQuery);
    typedQuery.setParameter(parameterPartialKey1, partialKey1);

    return typedQuery.getResultList();
}

实体如下所示:

@Entity
@Table(name = "TABLE_A", uniqueConstraints = 
@UniqueConstraint(columnNames = {
    "PARTIAL_KEY_1", "STRING_ATTR_1", "STRING_ATTR_2" }))
public class EntityA {
    @EmbeddedId
    @AttributeOverrides({
        @AttributeOverride(name = "partialKey1", column = @Column(name = "PARTIAL_KEY_1", nullable = false)),
        @AttributeOverride(name = "partialKey2", column = @Column(name = "PARTIAL_KEY_2", nullable = false))})
    private EntityAId id;
    @Column(name = "STRING_ATTR_1", nullable = false)
    private String stringAttribute1;
    @Column(name = "STRING_ATTR_2", nullable = false)
    private String stringAttribute2;
    @OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY, mappedBy = "entityA")
    private Set<EntityB> entityBs;

    // getters and setters omitted for brevity.
}

@Entity
@Table(name = "TABLE_2")
public class EntityB {
    @EmbeddedId
    @AttributeOverrides({
        @AttributeOverride(name = "partialKey3", column = @Column(name = "PARTIAL_KEY_3", nullable = false)),
        @AttributeOverride(name = "partialKey1", column = @Column(name = "PARTIAL_KEY_1", nullable = false)),
        @AttributeOverride(name = "partialKey2", column = @Column(name = "PARTIAL_KEY_2", nullable = false))})
    private EntityBId id;
    @Column(name = "VALUE")
    private String value;
    @ManyToOne(fetch = FetchType.LAZY)
    @JoinColumns({
        @JoinColumn(name = "PARTIAL_KEY_1", referencedColumnName = "PARTIAL_KEY_1", nullable = false, insertable = false, updatable = false),
        @JoinColumn(name = "PARTIAL_KEY_2", referencedColumnName = "PARTIAL_KEY_2", nullable = false, insertable = false, updatable = false)})
    private EntityA entityA;

    // getters and setters omitted for brevity.

}

最后是DTO:

public class EntityADto implements Serializable {
    private static final long serialVersionUID = -5343329086697620178L;

    private String partialKey1;
    private Integer partialKey2;
    private String stringAttribute1;
    private String stringAttribute2;
    private Map<String, String> additionalAttributes;

    public ProzessdatStandardDto() { }

    public ProzessdatStandardDto(String partialKey1,
                                 Integer partialKey2,
                                 String stringAttribute1,
                                 String stringAttribute2,
                                 Set<EntityB> entityBs) {
        this.partialKey1 = partialKey1;
        this.partialKey2 = partialKey2;
        this.stringAttribute1 = stringAttribute1;
        this.stringAttribute2 = stringAttribute2;

        final Map<String, String> entityBsConverted = new HashMap<>();
        if (!CollectionUtils.isEmpty(entityBs)) {
            for (EntityB entityB : entityBs) {
                entityBsConverted.put(entityB.getPartialKey3(), entityB.getValue());
            }
        }
        this.additionalAttributes = prozessdatExpansionsConverted;
    }

    // getters and setters omitted for brevity.
}

1 个答案:

答案 0 :(得分:0)

联接为您提供了sql中行结果的集合:

constructor_expression ::=
NEW constructor_name ( constructor_item {, constructor_item}* )

constructor_item ::=
single_valued_path_expression |
scalar_expression |
aggregate_expression |
identification_variable

,依此类推。没有将结果集合传递给构造函数的机制。

JPA规范4.14

Parent    Child    Child2
p1        c111     c121
p1        c121     
p1        c131     c122
p2        c211     c211
p2        c221     c212
p2        c231     

另外,另一个问题是您的查询可能返回多个父或子。

setState

我猜测原因是对于基础JPA提供程序而言,它变得太复杂了,以至于无法知道在何处进行拆分或将哪些值用于传递给子构造函数,或者可能是我不熟悉的更微妙的原因。最重要的是,它要求您提供用于解析此矩阵的代码,如果要执行此操作,则最好不使用JPA来解析结果。