Question

我有2个字符串

string str="nl/vacature/admin/Employee/home/details/"

和另一个

string template ="nl/vacature/{model}/{controller}/{Action}/{Method}/"

我在寻找

model=admin,controller=Employee,Action=home,Method=details

在对象或字典中为键-值格式。其URL和模板键的顺序可能不同

string template ="vacature/jobcount/{controller}/{Action}/{model}/{Method}/"

string str ="vacature/jobcount/Employee/home/admin/details/"

Answer 1

这是Regex解决方案，但是您需要稍微更改一下模板。

string url = "nl/vacature/admin/Employee/home/details/";
string template = "nl/vacature/(?<Model>.*?)/(?<Controller>.*?)/(?<Action>.*?)/(?<Method>.*?)/";
var matches = Regex.Match(url, template).Groups.Cast<Group>().Where(g => !int.TryParse(g.Name, out _)).ToDictionary(m => m.Name, m => m.Value);
// Dictionary<string, string>(4) { { "Model", "admin" }, { "Controller", "Employee" }, { "Action", "home" }, { "Method", "details" } }

但是，外部解析库可能更合适。您可以找到一些URL解析器，而不使用正则表达式。

Answer 2

尝试一下：

string url = "nl/vacature/admin/Employee/home/details/";
string template = "nl/vacature/{model}/{controller}/{Action}/{Method}/";

// remove unnecessary parts
template = template.Replace("nl/vacature/", "").Replace("{", "").Replace("}", "");
url = url.Replace("nl/vacature/", "");

// dictionary, that will hold pairs, that you want
var dict = new Dictionary<string,string>();

var urlList = url.Split('/');
var templateList = template.Split('/');

for(int i = 0; i < urlList.Length; i++) 
{
   dict.Add(templateList[i], urlList[i]);
}

如果URL不会包含相同数量的部分，我会为您提供异常处理。

如何从2个不同的字符串中获取字典中的值

2 个答案: