Question

我正在尝试重新格式化以下对象数组：

ON T2.ad_id = T1.ad_id

我要重新格式化：

SELECT T1.record_id,
       T1.ad_id,
       T1.gender,
       T1.gender_view,
       T1.time_entry
       COALESCE(T2.submitted_by, 0) submitted_by
FROM Table1 T1
LEFT JOIN Table2 T2 ON T2.ad_id = T1.ad_id

如何重新格式化此对象数组？谢谢

Answer 1

您可以使用map遍历数组。使用reduce将Attributes数组汇总为一个对象。

let users = [{"Username":"test1","Attributes":[{"Name":"sub","Value":"1234"},{"Name":"email","Value":"test1@gmail.com"}]},{"Username":"test2","Attributes":[{"Name":"sub","Value":"5678"},{"Name":"email","Value":"test2@gmail.com"}]}]

let result = users.map(({Username,Attributes}) => {
  let a = Attributes.reduce((c, v) => ({ ...c,[v.Name]: v.Value}), {});
  a.Username = Username;
  return a;
});

console.log(result);

更短版本：

let result = users.map(({Username, Attributes})=>({Username,...Attributes.reduce((c,v)=> ({...c, [v.Name]: v.Value}) ,{})}));

Answer 2

一种可能的解决方案是使用Array.map()将每个原始object映射到一个新的。在map()内部，您可以遍历Attributes数组，将属性添加到将要返回的新object中。

let users =[
  {
    Username: "test1",
    Attributes:[
      {Name: "sub", Value:"1234"},
      {Name:"email", Value:"test1@gmail.com"}
    ]
  },
  {
    Username: "test2",
    Attributes: [
      {Name: "sub", Value:"5678"},
      {Name:"email", Value:"test2@gmail.com"}
    ]
  }
];

let res = users.map(({Username, Attributes}) =>
{
    let newObj = {Username};    
    Attributes.forEach(({Name, Value}) => newObj[Name] = Value);
    return newObj;
});

console.log(res);

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.as-console-wrapper {max-height:100% !important; top:0;}

Answer 3

您可以使用for...of遍历用户。通过Attributes循环将具有2个属性的每个对象转换为键值对。使用Object.assign()

创建合并的对象

const users=[{Username:"test1",Attributes:[{Name:"sub",Value:"1234"},{Name:"email",Value:"test1@gmail.com"}]},{Username:"test2",Attributes:[{Name:"sub",Value:"5678"},{Name:"email",Value:"test2@gmail.com"}]}];

const output = [];

for(const { Username, Attributes } of users) {
  const attributes = Attributes.map(({ Name, Value }) => ({ [Name]: Value }));
  output.push(Object.assign({ Username }, ...attributes))
}

console.log(output)

重新格式化对象数组

3 个答案: