Question

我有以下2张桌子：

表：产品

+----+---------+-------------+
| id |  fn_id  | created_at  |
+----+---------+-------------+
|  1 |    4    |  SOME TIME  |
|  2 |    5    |  SOME TIME  |
|  3 |    6    |  SOME TIME  |
|  4 |    10   |  SOME TIME  |
|  5 |    10   |  SOME TIME  |
+----+---------+-------------+

表Fn

+----+---------+-------------+
| id |  fn_id  | created_at  |
+----+---------+-------------+
|  1 |    10   |  SOME TIME  |
|  2 |    11   |  SOME TIME  |
|  3 |    12   |  SOME TIME  |
|  4 |    14   |  SOME TIME  |
+----+---------+-------------+

还有一个给我一个时间戳（$ user_timestamp）的用户输入。

现在我需要获取所有产品，其中

products.fn_id is 10 
fn.fn_id is 10  
fn.created == $user_timestamp

产品模型具有以下关系：

public function fn() {
        return $this->hasMany('App\FN', 'fn_id', 'fn_id');
}

现在，我已经尝试了多种方法，例如where查询，我想检查两者的fn_id是否为“ 10”，并且fn表的created_at值等于$ user_timestamp。

但是，我无法做到。

$products = Products::with('fn')->where('fn.fn_id', function ($query) use ($user_timestamp) {
            $query->where([['fn_id', 10],['created_at', $user_timestamp]]);
        })->get();

Answer 1

您将不得不使用whereHas来基于Products约束fn。

$products = Products::with('fn')->whereHas('fn', function($q) use($user_timestamp){
    $q->where('fn_id', 10)->where('created_at', $user_timestamp);
})->get();

Answer 2

尝试

$id_to_search=10;
$products = Products::with('fn')->where('fbn_id',$id_to_search)->whereHas('fn', function($q) use($user_timestamp,$id_to_search){
    $q->where('fn_id', $id_to_search)->where('created_at', $user_timestamp);
})->get();

Laravel-从其他表中的Table where子句获取数据

2 个答案: