Question

该函数应在当前日期之后返回一个新日期，并添加num_of_flows。 num_of_flows是一个整数值

ALTER  function [dbo].[M20_22_GetLoanMaturityDate_FIN_10]
(
    @AcctAcid varchar(50),
    @ScheduleNum varchar(50),
    @bank_id varchar(6) = '03'
)
returns varchar(50)
as 
BEGIN
    Declare @lMaturityDate varchar(50)
    begin
            select @lMaturityDate = 
            case Finacle_Lrs.LR_FREQ_TYPE   
                             when 'W' then  dateadd(day, (Finacle_Lrs.NUM_OF_FLOWS - 1) * 7,Finacle_Lrs.FLOW_START_DATE)
                             when 'F' then  dateadd(day, (Finacle_Lrs.NUM_OF_FLOWS - 1) * 14,Finacle_Lrs.FLOW_START_DATE)
                             when 'M' then  (dateadd(month, Finacle_Lrs.NUM_OF_FLOWS - 1, Finacle_Lrs.FLOW_START_DATE))
                             when 'Q' then  (dateadd(month, (Finacle_Lrs.NUM_OF_FLOWS - 1) * 3, Finacle_Lrs.FLOW_START_DATE))
                             when 'H' then  dateadd(month, (Finacle_Lrs.NUM_OF_FLOWS - 1) * 6, Finacle_Lrs.FLOW_START_DATE)
                             when 'Y' then  dateadd(month, (Finacle_Lrs.NUM_OF_FLOWS - 1) * 12, Finacle_Lrs.FLOW_START_DATE)
                      end
            from    [TEST_EIMDW_Archive].[ARCHOWN].[FINCL10_LRS] Finacle_Lrs
            where   Finacle_Lrs.acid = @AcctAcid
            and Finacle_Lrs.shdl_num = @ScheduleNum
            and Finacle_Lrs.FLOW_ID in ('PRDEM','EIDEM')
            AND Finacle_Lrs.ACTIVE_FLAG = 'Y' AND Finacle_Lrs.DELETE_FLAG= 'N'
            and Finacle_Lrs.bank_id = @bank_id
            and Finacle_Lrs.FLOW_START_DATE = ( select max(a.FLOW_START_DATE)
                            from   [TEST_EIMDW_Archive].[ARCHOWN].[FINCL10_LRS] a
                            where  a.ACID = Finacle_Lrs.ACID
                                and    a.SHDL_NUM = Finacle_Lrs.SHDL_NUM
                            and    a.FLOW_ID in ('PRDEM', 'EIDEM') AND a.ACTIVE_FLAG = 'Y' AND a.DELETE_FLAG='N' and a.bank_id = @bank_id
        );
end
        return isnull(@lMaturityDate,null);

END

做完一些检查后，我注意到在比较oracle数据库上的原始代码时，有一天低估了19629行。请查看oracle版本的代码：

FUNCTION GetLoanMaturityDate(AcctAcid VARCHAR2, ScheduleNum VARCHAR2) RETURN DATE IS
        lMaturityDate DATE;
    BEGIN
        begin
            select decode(lrs.LR_FREQ_TYPE, 'W', lrs.FLOW_START_DATE + (lrs.NUM_OF_FLOWS - 1) * 7,
                            'F', lrs.FLOW_START_DATE + (lrs.NUM_OF_FLOWS - 1) * 14,
                            'M', add_months(lrs.FLOW_START_DATE, lrs.NUM_OF_FLOWS - 1) ,
                            'Q', add_months(lrs.FLOW_START_DATE, (lrs.NUM_OF_FLOWS - 1) * 3),
                            'H', add_months(lrs.FLOW_START_DATE, (lrs.NUM_OF_FLOWS - 1) * 6),
                            'Y', add_months(lrs.FLOW_START_DATE, (lrs.NUM_OF_FLOWS - 1) * 12)
                     )
            into    lMaturityDate
            from    lrs
            where   lrs.acid = AcctAcid
            and lrs.shdl_num = ScheduleNum
            and lrs.FLOW_ID in ('PRDEM','EIDEM')
            and lrs.FLOW_START_DATE = ( select max(a.FLOW_START_DATE)
                            from   lrs a
                            where  a.ACID = lrs.ACID
                                and    a.SHDL_NUM = lrs.SHDL_NUM
                            and    a.FLOW_ID in ('PRDEM', 'EIDEM')
                               ) ;
        exception
            when no_data_found then
                lMaturityDate:=NULL;
        end;

        return lMaturityDate;
    END GetLoanMaturityDate;

这也是我运行以查看不正确行的比较查询：

SELECT eim.acid as eim_acid,it.[ACID] as it_acid,
eim.[MATURITY_DATE] as eim_maturity_date,it.[MATURITY_DATE] as it_maturity_date ,
eim.[DAYS_TO_MATURITY] as eim_DAYS_TO_MATURITY,it.[DAYS_TO_MATURITY] as it_DAYS_TO_MATURITY,(it.[DAYS_TO_MATURITY]-eim.[DAYS_TO_MATURITY]) as diff
FROM [TEST_EIMDW_BOJ_REPORTS].[BOJOWN].[loans_maturity_profile] eim 
inner join [dbo].[IT_LOANS_MATURITY_PROFILE] it on eim.acid= it.acid
where eim.MATURITY_DATE != it.MATURITY_DATE

最后，下面是查询结果，显示了正确结果集的比较与我当前试图在sql服务器上修复的结果的比较：

Answer 1

Oracle的add_months()和SQL Server的dateaddd(month)具有不同的语义，尤其是在月底。

所以：

select add_months(date '2019-02-28', 1)
from dual

--> 2019-03-31

（请参阅db<>fiddle）

位置：

select dateadd(month, 1, '2019-02-28')

--> 2019-03-28

（请参阅db<>fiddle）

在SQL Server中模拟Oracle行为可能会有些棘手。我什至不确定这是否可取。

Answer 2

就像戈登所说的那样，Oracle ADD_MONTHS函数的确切行为是，如果源日期是该月的最后一天，则返回日期也是结果月份的最后一天（不论来源日期的月长短。

SQL Server没有类似的功能。

哪种实现是正确的，或者是否重要，将取决于您的特定情况。

Answer 3

SQL Server“月末”-EOMONTH（start_date [，month_to_add]）函数在该月的最后一天的行为类似于ORACLE add_months。

DATEADD未为某些行返回正确的日期

3 个答案: