如何获得阵列中5分钟间隔内的最后几个小时？

Question

我做到了

var date, array = [];
date = new Date();

while (date.getMinutes() % interval !== 0) {
    date.setMinutes ( date.getMinutes() + 1 );
}

// A whole day has 24 * 4 quarters of an hour
// Let's iterate using for loop
for (var i = 0; i < 24 * (60/interval); i++) {
    array.push(date.getHours() + ':' + date.getMinutes());
    date.setMinutes ( date.getMinutes() + interval);
}

console.log(array.slice(0,10));

我接下来的5个小时是几个小时。

现在是16:30

(10) ["16:35", "16:40", "16:45", "16:50", "16:55", "17:0", "17:5", "17:10", "17:15", "17:20"]

如何调整我的代码以在5分钟的间隔内获得最后几个小时？

现在是16:30，我想得到这些

(10) ["16:25", "16:20", "16:15", "16:10", "16:05", "16:0", "15:55", "15:45", "15:35", "15:35"]

Answer 1

要后退而不是前进，请将+ interval更改为- interval。要在过去（而不是未来）中四舍五入到最近的5分钟，请在将setMinutes() 推入数组之前进行date.setMinutes(date.getMinutes() - interval); array.push(date.getHours() + ':' + date.getMinutes());

var date, array = [];
date = new Date();
const interval = 5;

while (date.getMinutes() % interval !== 0) {
  date.setMinutes(date.getMinutes() + 1);
}

// A whole day has 24 * 4 quarters of an hour
// Let's iterate using for loop
for (var i = 0; i < 24 * (60 / interval); i++) {
  date.setMinutes(date.getMinutes() - interval);
  array.push(date.getHours() + ':' + date.getMinutes());
}

console.log(array.slice(0, 10));

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