如何在子字符串SQL中搜索特殊字符

Question

您好，基本上我有一个付款列，其值为0，$ [amt]或[amt]％，我如何搜索包含％的子字符串？现在我正在做

select * from table where not Payment like '$%' and not Payment =0

检索子字符串中包含％的所有行

Answer 1

您可以尝试使用％\％（转义％）

select * from table where not Payment like '%\%' and not Payment =0

Answer 2

MySQL 5.6

SELECT
    * 
FROM 
    PAYMENT 
WHERE 
    AMOUNT NOT LIKE '$\%%' 
AND 
    CONVERT(SUBSTRING(AMOUNT, 2), SIGNED INTEGER) = 0;

sqlfiddle

Oracle 11g R2

SELECT
   *
FROM 
    PAYMENT 
WHERE 
    AMOUNT NOT LIKE '$\%%' 
AND
    SUBSTR(AMOUNT, 2) LIKE '0' ESCAPE '\';

sqlfiddle

Answer 3

这回答了用SQLite标记的原始问题。
您可以使用ESCAPE（在SQL As Understood By SQLite处找到更多信息）：

select * from tablename where Payment like '%#%' ESCAPE '#'

转义字符'#'之后的字符被视为字符串文字，而不是通配符。
请参见demo。

CREATE TABLE tablename (
    Payment TEXT
);
INSERT INTO tablename (Payment) VALUES 
 ('0'),
 ('15%'),
 ('$55'),
 ('3%');

结果：

| Payment |
| ------- |
| 15%     |
| 3%      |