嗨，我在保存多个具有不同名称的复选框时遇到问题 我对菜单具有案例创建权限，并且菜单具有不同的访问权限，例如创建，读取，更新，删除等
我尝试使用此代码，但结果无效
这是我的刀片模板
<android.support.constraint.ConstraintLayout
xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent">
<!--<RelativeLayout-->
<!--android:layout_width="wrap_content"-->
<!--android:layout_height="wrap_content">-->
<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_marginStart="8dp"
android:layout_marginTop="8dp"
android:layout_marginEnd="8dp"
android:layout_marginBottom="8dp"
android:text="A"
android:textSize="20sp"
android:textColor="#000"
android:textStyle="bold"
app:layout_constraintBottom_toBottomOf="parent"
app:layout_constraintEnd_toEndOf="parent"
app:layout_constraintStart_toStartOf="parent"
app:layout_constraintTop_toTopOf="parent" />
<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_marginStart="8dp"
android:layout_marginTop="8dp"
android:layout_marginEnd="8dp"
android:layout_marginBottom="8dp"
android:text="SAMPLE TWO"
android:textSize="10sp"
app:layout_constraintBottom_toBottomOf="parent"
app:layout_constraintEnd_toEndOf="parent"
app:layout_constraintStart_toStartOf="parent"
app:layout_constraintTop_toTopOf="parent" />
<!--</RelativeLayout>-->
</android.support.constraint.ConstraintLayout>
这里是我的存储方法
<div class="table-responsive">
<table id="bs4-table" class="table table-striped table-bordered" style="width:100%">
<thead>
<tr>
<th>No</th>
<th>Menu</th>
<th>Create</th>
<th>Read</th>
<th>Update</th>
<th>Delete</th>
<th>Approve</th>
<th>Export PDF</th>
<th>Export Excel</th>
</thead>
<tbody>
@foreach ($permission_menus as $permission_menu)
<tr>
<td>{{ $loop->iteration }}</td>
<td>
{{ $permission_menu->name }} <input type="checkbox" name="menus_id[]" value="{{ $permission_menu->id }}">
</td>
<td>
<input type="checkbox" name="create_access[]" value="0" onclick="changeFlag(this)">
</td>
<td>
<input type="checkbox" name="read_access[]" value="0" onclick="changeFlag(this)">
</td>
<td>
<input type="checkbox" name="update_access[]" value="0" onclick="changeFlag(this)">
</td>
<td>
<input type="checkbox" name="delete_access[]" value="0" onclick="changeFlag(this)">
</td>
<td>
<input type="checkbox" name="approve_access[]" value="0" onclick="changeFlag(this)">
</td>
<td>
<input type="checkbox" name="export_pdf_access[]" value="0" onclick="changeFlag(this)">
</td>
<td>
<input type="checkbox" name="export_excel_access[]" value="0" onclick="changeFlag(this)">
</td>
</tr>
@endforeach
</tbody>
</table>
</div>
有人知道如何解决此问题吗？还是有任何解决办法？
答案 0 :(得分：0)
如果取消选中菜单项之一而未取消选中该菜单下的所有权限，则结果将不一致。您可以始终强制将标识符作为菜单索引：
<div class="table-responsive">
<table id="bs4-table" class="table table-striped table-bordered" style="width:100%">
<thead>
<tr>
<th>No</th>
<th>Menu</th>
<th>Create</th>
<th>Read</th>
<th>Update</th>
<th>Delete</th>
<th>Approve</th>
<th>Export PDF</th>
<th>Export Excel</th>
</tr>
</thead>
<tbody>
@foreach ($permission_menus as $permission_menu)
<tr>
<td>{{ $loop->iteration }}</td>
<td>
{{ $permission_menu->name }} <input type="checkbox" name="menus_id[]"
value="{{ $permission_menu->id }}">
</td>
<td>
<input type="checkbox" name="create_access[{{$permission_menu->id}}]" value="0" onclick="changeFlag(this)">
</td>
<td>
<input type="checkbox" name="read_access[{{$permission_menu->id}}]" value="0" onclick="changeFlag(this)">
</td>
<td>
<input type="checkbox" name="update_access[{{$permission_menu->id}}]" value="0" onclick="changeFlag(this)">
</td>
<td>
<input type="checkbox" name="delete_access[{{$permission_menu->id}}]" value="0" onclick="changeFlag(this)">
</td>
<td>
<input type="checkbox" name="approve_access[{{$permission_menu->id}}]" value="0" onclick="changeFlag(this)">
</td>
<td>
<input type="checkbox" name="export_pdf_access[{{$permission_menu->id}}]" value="0"
onclick="changeFlag(this)">
</td>
<td>
<input type="checkbox" name="export_excel_access[{{$permission_menu->id}}]" value="0"
onclick="changeFlag(this)">
</td>
</tr>
@endforeach
</tbody>
</thead>
</table>
这样，您可以正确匹配结果：
public function store(Request $request)
{
$this->validate($request, [
'user_access' => 'required',
], [
'user_access.required' => 'User harus dipilih!',
]);
foreach($request->menus_id as $menu_id)
{
$create_access = $request->create_access;
$read_access = $request->read_access;
$update_access = $request->update_access;
$delete_access = $request->delete_access;
$approve_access = $request->approve_access;
$export_pdf_access = $request->export_pdf_access;
$export_excel_access = $request->export_excel_access;
if (!isset($create_access[$menu_id])) {
$create_access[$menu_id] = 0;
}
if(!isset($read_access[$menu_id])){
$read_access[$menu_id] = 0;
}
if(!isset($update_access[$menu_id])){
$update_access[$menu_id] = 0;
}
if(!isset($delete_access[$menu_id])){
$delete_access[$menu_id] = 0;
}
if(!isset($approve_access[$index])){
$approve_access[$index] = 0;
}
if(!isset($export_pdf_access[$menu_id])){
$export_pdf_access[$menu_id] = 0;
}
if(!isset($export_excel_access[$menu_id])){
$export_excel_access[$menu_id] = 0;
}
$permission = [
'menu_id' => $menu_id,
'create_access' => $create_access[$menu_id],
'read_access' => $read_access[$menu_id],
'update_access' => $update_access[$menu_id],
'delete_access' => $delete_access[$menu_id],
'approve_access' => $approve_access[$menu_id],
'export_pdf_access' => $export_pdf_access[$menu_id],
'export_excel_access' => $export_excel_access[$menu_id],
'user_id' => $request->user_id,
'user_access' => $request->user_access
];
DB::table('permissions')->insert($permission);
}
return redirect()->back()->with('success', 'Hak akses berhasil di set!');
}
注意：除了执行if(!isset($x[$menu_id])) { $x[$menu_id] = 0; }之外，您还可以在$x[$menu_id]??0数组中执行$permission