Question

来自Specified Twice Table for 'DELETE' in MariaDB的引用

在我将引用中的查询实现到代码中之后，我在yii2中出错了

查询：

public function actionDeleteduplicate($date){
        Yii::$app->db->createCommand("DELETE t1
                                    FROM HrAttLogsFormatted t1
                                    INNER JOIN
                                    (
                                        SELECT FingerId, MIN(CreatedDate) AS MinCreatedDate
                                        FROM HrAttLogsFormatted 
                                        WHERE DateIn = '".$date."' AND Late != ''
                                        GROUP BY FingerId
                                        HAVING COUNT(FingerId) > 1
                                    ) t2
                                        ON t1.FingerId = t2.FingerId AND t1.CreatedDate = t2.MinCreatedDate
        ")->queryAll();

        $this->redirect(['index']);
    }

结果：

SQLSTATE [HY000]：常规错误正在执行的SQL是：DELETE t1 FROM HrAttLogsFormatted t1 INNER JOIN（SELECT FingerId， MIN（CreatedDate）AS MinCreatedDate从HrAttLogsFormatted WHERE DateIn ='2019-05-03'和后期！=''GROUP BY FingerId HAVING COUNT（FingerId）> 1）t2在t1.FingerId = t2.FingerId和 t1.CreatedDate = t2.MinCreatedDate

有人知道代码有什么问题吗？

Answer 1

该问题可能与您在delete和子查询中具有相同表的事实有关。尝试通过嵌套查询强制数据库引擎使用临时表：

DELETE t1
FROM HrAttLogsFormatted t1
INNER JOIN ( 
  select FingerId, MinCreatedDate
  FROM   (
    SELECT FingerId, MIN(CreatedDate) AS MinCreatedDate
    FROM HrAttLogsFormatted 
    WHERE DateIn = '".$date."' AND Late != ''
    GROUP BY FingerId
    HAVING COUNT(FingerId) > 1
  ) t3 
) t2  ON t1.FingerId = t2.FingerId AND t1.CreatedDate = t2.MinCreatedDate

顺便说一句：您不应该直接在SQL中使用PHP变量，而应该看看binding params。

SQLSTATE [HY000]：常规错误Yii2中正在执行SQL

1 个答案: