我需要将我的第一个MongoDB查询获得的 state.name 值放入下一组MongoDB查询中。当我console.log我的第一个查询时,我达到了预期的结果,但是在以下查询中显示为undefined。它们是异步的还是我传递的错误?
我研究了在Express + MongoDB中将一个查询的结果传递给下一个查询的示例,并研究了Promises-不确定我是否完全理解。
// GET State Home
router.get('/:stateid', ensureAuthenticated, (req, res) => {
const member = req.user;
console.log(member);
Promise.all([
state = States.findOne({url:req.params.stateid}),
statelegislation = StateLegislation.find({'state': state.name }),
statepolicy = StatePolicy.find({'state': state.name }),
stateregulation = StateRegulation.find({'state': state.name }),
statelitigation = StateLitigation.find({'state': state.name }),
]).then(([state,statelegislation,statepolicy,stateregulation,statelitigation]) =>
res.render('app/state/home', {
state:state,
statelegislation:statelegislation,
statepolicy:statepolicy,
stateregulation:stateregulation,
statelitigation:statelitigation,
}))
.catch(err => res.send('Ops, something has gone wrong'));
});
在以下查询中传递字符串值而不是变量 state.name 时,我将获得该值所需的结果。
我无法从第一个MongoDB请求中动态传递值。
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答案 0 :(得分:0)
您不能一次Promise.all
一次完成该操作。您需要先等待state
承诺,然后再开始其余查询:
router.get('/:stateid', ensureAuthenticated, (req, res) => {
const member = req.user;
console.log(member);
States.findOne({url:req.params.stateid}).then(state =>
Promise.all([
StateLegislation.find({'state': state.name }),
StatePolicy.find({'state': state.name }),
StateRegulation.find({'state': state.name }),
StateLitigation.find({'state': state.name }),
]).then(([statelegislation,statepolicy,stateregulation,statelitigation]) =>
res.render('app/state/home', {
state,
statelegislation,
statepolicy,
stateregulation,
statelitigation,
})
)
)
.catch(err => res.send('Ops, something has gone wrong'));
});