如何显示名称而不是电子邮件地址。我正在使用PasswordResetView,并且已经在settings.py中配置了此电子邮件。当我仅在EMAIL_HOST_USER中仅使用电子邮件地址时,它可以正常工作,但是在我更改为显示名称后,它不起作用。我该怎么解决
settings.py
EMAIL_BACKEND = 'django.core.mail.backends.smtp.EmailBackend'
EMAIL_USE_TLS = True
EMAIL_HOST = 'smtp.gmail.com'
EMAIL_HOST_USER = "CompanyName <company@gmail.com>"
EMAIL_HOST_PASSWORD = 'password'
EMAIL_PORT = '587'
urls.py
path('password-reset/',
auth_views.PasswordResetView.as_view(template_name='students/password_reset.html',
email_template_name='students/password_reset_email.html',
success_url=reverse_lazy('students:password_reset_done')),
name='password_reset'),
path('password-reset/done/',
auth_views.PasswordResetDoneView.as_view(template_name='students/password_reset_done.html'),
name='password_reset_done'),
path('password-reset-confirm/<uidb64>/<token>/',
auth_views.PasswordResetConfirmView.as_view(template_name='students/password_reset_confirm.html',
success_url=reverse_lazy('students:password_reset_complete')
), name='password_reset_confirm'),
path('password-reset-complete/',
auth_views.PasswordResetCompleteView.as_view(template_name='students/password_reset_complete.html'),
name='password_reset_complete'),
答案 0 :(得分:1)
传递 from_email
中的 as_view()
参数。
path('password-reset/',
auth_views.PasswordResetView.as_view(template_name='students/password_reset.html',
email_template_name='students/password_reset_email.html',
success_url=reverse_lazy('students:password_reset_done',),
from_email="CompanyName <company@gmail.com>"),
name='password_reset'),
EMAIL_HOST_USER
设置在这种情况下不起作用。因此,将其更改回原始状态。