我即将使用Web服务开发Web应用程序。我已经调整了jax-ws和ws-security。我使用了soapUI并发送了下一个请求:
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:soap="..." >
<soapenv:Header>
<wsse:Security xmlns:wsse="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd" soapenv:mustUnderstand="1">
<wsu:Timestamp xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd" wsu:Id="Timestamp-2">
<wsu:Created>2011-11-11T00:05:05.044Z</wsu:Created>
<wsu:Expires>2012-11-11T00:10:05.044Z</wsu:Expires>
</wsu:Timestamp>
<wsse:UsernameToken xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd" wsu:Id="UsernameToken-1">
<wsse:Username>user</wsse:Username>
<wsse:Password>password</wsse:Password>
</wsse:UsernameToken>
</wsse:Security>
</soapenv:Header>
<soapenv:Body>
<soap:foo>
<arg0>1</arg0>
</soap:foo>
</soapenv:Body>
</soapenv:Envelope>
我需要从标题中获取用户名和密码。在应用程序上,我可以通过下一个代码获得它:
@Resource
WebServiceContext context;
...
private static final String PRINCIPAL_RESULT = "wss4j.principal.result";
...
WSUsernameTokenPrincipal wsutp = (WSUsernameTokenPrincipal) context.getMessageContext().get(PRINCIPAL_RESULT);
..
String user = wsutp.getName()
String password = wsutp.getPassword();
但我不知道应该如何使用jUnit测试来测试它,因为测试类上的 context.getMessageContext()将为NULL 。
有谁知道一个好的指南或提供代码示例?
答案 0 :(得分:1)
您需要模拟junit测试中不可用的资源。请看一下像Mokito(http://mockito.org/)这样的框架。在那里你可以做s.th.像:
//You can mock concrete classes, not only interfaces
LinkedList mockedList = mock(LinkedList.class);
//stubbing
when(mockedList.get(0)).thenReturn("first");
when(mockedList.get(1)).thenThrow(new RuntimeException());
或者你的情况:
WSUsernameTokenPrincipal mockedWsutp = mock(WSUsernameTokenPrincipal.class);
when(mockedWsutp.getName()).thenReturn("TheNameRequiredForYourTestCase");
...
使用这些框架,您可以模拟不可用的资源。它们很容易与junit集成。我希望这提供了一些有用的想法。
答案 1 :(得分:0)
试试这个: 使用XWS-Security(纯文本密码)保护JAX-WS Web服务 [http://mananvpanchal.blogspot.com/2010/06/jax-ws-webservice-with-plaintext.html][1]