Question

我有以下雄辩的实体：

电影
MovieSession
MovieTheater
MovieTheaterRoom

表结构：

Schema::create('movies', function (Blueprint $table) {
    $table->increments('id');
});

Schema::create('movie_theaters', function (Blueprint $table) {
    $table->increments('id');
    $table->string('name')->index();
    $table->string('slug')->index()->unique();
    $table->string('description')->index()->nullable();
    $table->longText('content')->nullable();

    $table->unsignedInteger('picture_id')->nullable();
    $table->foreign('picture_id')
         ->references('id')
         ->on('media');

    $table->boolean('activated')->default(true);

    $table->timestamps();
});

Schema::create('movie_theater_rooms', function (Blueprint $table) {
    $table->increments('id');
    $table->string('name')->index();
    $table->string('description')->index()->nullable();
    $table->longText('content')->nullable();

    $table->boolean('activated')->default(true);

    $table->unsignedInteger('movie_theater_id');
    $table->foreign('movie_theater_id')
        ->references('id')
        ->on('movie_theaters')
        ->onDelete('cascade');

    $table->unsignedInteger('picture_id')->nullable();
    $table->foreign('picture_id')
        ->references('id')
        ->on('media');

    $table->timestamps();
});

Schema::create('movie_sessions', function (Blueprint $table) {
    $table->increments('id');

    $table->dateTime('starts_in');
    $table->dateTime('ends_in');

    $table->unsignedInteger('movie_theater_room_id');
    $table->foreign('movie_theater_room_id')
        ->references('id')
        ->on('movie_theater_rooms')
        ->onDelete('cascade');

    $table->unsignedInteger('movie_id');
    $table->foreign('movie_id')
        ->references('id')
        ->on('movies')
        ->onDelete('cascade');

    $table->boolean('activated')->default(true);

    $table->timestamps();
});

其中 MovieTheater 具有许多 MovieTheaterRoom ，每个 MovieTheaterRoom 具有许多 MovieSession 和每个 MovieSession < / strong>属于电影。

我正在尝试的是，通过$movieTheaterId在今天的 MovieTheater 上播放今天正在播放的所有 Movie ，但是由于时间长关系，我无法检索此类集合。

这是我尝试过的：

public function scopeGetMoviesShowingTodayOnMovieTheater($movieTheaterId) { return Movie::whereHas('sessions', function ($query) use ($movieTheaterId) { // $query->whereDate('starts_in', Carbon::today()); $query->whereHas('movieTheaterRoom', function ($query) use ($movieTheaterId) { $query->where('movie_theater_id', $movieTheaterId); }); }); }

致电App\Models\Movie::getMoviesShowingTodayOnMovieTheater(1)->get()时，这就是我得到的：

PHP可恢复的致命错误：不能在行338上的... / vendor / illuminate / support / Str.php中将类Illuminate / Database / Eloquent / Builder的对象转换为字符串

我也曾尝试像这样使用此软件包staudenmeir/eloquent-has-many-deep：

class MovieTheater extends Model { use HasRelationships; public function movies() { return $this->hasManyDeep(Movie::class, [MovieSession::class, MovieTheaterRoom::class]); } }

并且在致电App\Models\MovieTheater::find(1)->movies()->get()
时
这是输出：

带有消息“ SQLSTATE [42S22]”的Illuminate / Database / QueryException：找不到列：1054“字段列表”中的未知列“ movie_sessions.movie_theater_id”（SQL：选择movies。*，movie_sessions 。movie_theater_id来自{{1}上的movies内部联接movie_theater_rooms。movie_theater_rooms = id。movies内部联接movie_theater_room_id在movie_sessions上。movie_sessions = id。movie_theater_rooms其中movie_session_id。movie_sessions = 1）'

我错了吗？

Answer 1

例外

Illuminate / Database / Eloquent / Builder类的对象无法在第338行的... / vendor / illuminate / support / Str.php中转换为字符串

之所以抛出

，是因为您没有在范围定义中提供$ query参数。您的代码将尝试将电影院ID转换为Builder实例，这将失败。

尝试将代码重构为此：

/**
 * Scope a query to only select movies that are showing in a certain theater.
 *
 * @param  \Illuminate\Database\Eloquent\Builder  $query
 * @param  int  $movieTheaterId
 * @return \Illuminate\Database\Eloquent\Builder
 */
public function scopeGetMoviesShowingTodayOnMovieTheater($query, $movieTheaterId)
{
    return $query
        ->whereHas('sessions.movieTheaterRoom', function ($query) use 
        ($movieTheaterId) {
            $query->whereMovieTheaterId($movieTheaterId);
        });
}

我还在whereHas语句中添加了点符号来查询嵌套关系。

Answer 2

如果您想使用staudenmeir/eloquent-has-many-deep，则应按以下顺序进行订购

class MovieTheater extends Model {
    use HasRelationships;

    public function movies()
    {
        return $this->hasManyDeep(Movie::class, [MovieTheaterRoom::class, MovieSession::class]);
    }
}

示例订单：

如何获取在MovieTheater上播放的所有电影？

2 个答案: