提取li项并将其打印在一行中

Question

我想使用xpath 1.0提取以下内容的li项，并在不换行的情况下将其输出到一行。

这是我尝试过的

// * [@ id =“ shows”] / div / ol [2] / li / ol / li / a / text（）

<ol class="shows">
    <li>
        <strong>THEATRE by Rhodes</strong>
        <ol>
            <li data-id="0031-45076">
                <a class="action showtime" href="/booking/0031-45076">2:30pm </a>
            </li>
            <li data-id="0031-45077">
                <a class="action showtime" href="/booking/0031-45077">5:30pm </a>
            </li>
            <li data-id="0031-45079">
                <a class="action showtime" href="/booking/0031-45079">11:15pm </a>
            </li>
        </ol>
    </li>
    <li>
        <strong>Standard</strong>
        <ol>
            <li data-id="0031-44928">
                <a class="action showtime" href="/booking/0031-44928">11:00am </a>
            </li>
            <li data-id="0031-44929">
                <a class="action showtime" href="/booking/0031-44929">1:30pm </a>
            </li>
            <li data-id="0031-44930">
                <a class="action showtime" href="/booking/0031-44930">4:00pm </a>
            </li>
            <li data-id="0031-44931">
                <a class="action showtime" href="/booking/0031-44931">6:30pm </a>
            </li>
            <li data-id="0031-44932">
                <a class="action showtime" href="/booking/0031-44932">9:00pm </a>
            </li>
            <li data-id="0031-44933">
                <a class="action showtime" href="/booking/0031-44933">11:30pm </a>
            </li>
        </ol>
    </li>
</ol>