我正在使用sequelize
(4.42.0)和express。我有两个表categories
和main_categories
,它们具有以下关联:
db.main_categories.hasMany(db.categories);
db.categories.belongsTo(db.main_categories);
我尝试使用以下sequelize命令获取归类在其主要类别下的所有类别的列表:
var _categoryList = await models.main_categories.findAll({include: [{model: models.categories}], group:['main_categories.id']});
res.send({category_list: _categoryList});
上述序列化代码的输出为:
{
"category_list": [
{
"id": 1,
"name": "Physics",
"created_at": null,
"updated_at": null,
"categories": [
{
"id": 1,
"name": "Mechanics",
"created_at": "2019-03-21T03:39:48.000Z",
"updated_at": "2019-03-21T03:39:48.000Z",
"main_category_id": 1
}
]
},
{
"id": 2,
"name": "Chemistry",
"created_at": null,
"updated_at": null,
"categories": [
{
"id": 6,
"name": "General and Physical Chemistry",
"created_at": "2019-03-21T03:42:54.000Z",
"updated_at": "2019-03-21T03:42:54.000Z",
"main_category_id": 2
}
]
},
{
"id": 3,
"name": "Zoology",
"created_at": null,
"updated_at": null,
"categories": []
},
{
"id": 4,
"name": "Botany",
"created_at": null,
"updated_at": null,
"categories": []
}
]
}
对我来说,预期的输出是每个main_category中的categorys数组将包含属于同一主要类别的所有类别的详细信息,而不仅仅是上面输出中所示的一个。
答案 0 :(得分:0)
因此,我后来发现,由于已经声明了关联,因此我们只需要包含没有任何groupby子句的模型即可。所以对我有用的最终代码是:
var _categoryList = await models.main_categories.findAll({include: [{model: models.categories}]});