轻松的任务使我很难受。我想从不同的表中选择一列,并将其插入结果表中。基本上,就像所有工会一样:
SELECT Email FROM TableA
UNION ALL
Select Email FROM TableB
以此类推...
但是,我想以自动化方式进行此操作。正如我所说,这似乎很简单,但我对此绊脚石。我的代码尝试:
USE MyDatabase
IF OBJECT_ID ('TEMPDB..#Selection') IS NOT NULL DROP TableA #Selection;
SELECT Name AS TableA, ROW_NUMBER() OVER ( ORDER BY (SELECT 1)) AS RowNumb
INTO #Selection
FROM Sys.TableAs AS T
WHERE NAME LIKE '%abc%'
ORDER BY 2
IF OBJECT_ID ('TEMPDB..#Result') IS NOT NULL DROP TableA #Result;
CREATE TableA #Result ( Email VARCHAR (200))
DECLARE @Counter INT
SET @Counter = 1
WHILE @Counter <= ( SELECT MAX (RowNumb) FROM #Selection )
BEGIN
DECLARE @Table VARCHAR (100)
SET @Table = ( SELECT TableA FROM #Selection WHERE RowNumb = @Counter )
-- PRINT @Table SET @Counter = @Counter + 1 END
INSERT INTO #Result
SELECT Email
FROM @Table
SET @Counter = @Counter + 1
END
我确信有人会很快发现我的错误。非常感谢您的指导!
亲切的问候,M。
答案 0 :(得分:3)
我会(个人)去做这样的事情:
CREATE TABLE #Email (email nvarchar(200));
DECLARE @SQL nvarchar(MAX);
SET @SQL = N'INSERT INTO #Email (Email)' + NCHAR(13) + NCHAR(10) +
STUFF((SELECT NCHAR(13) + NCHAR(10) +
N'UNION ALL' + NCHAR(13) + NCHAR(10) +
N'SELECT CONVERT(nvarchar(200),email)' + NCHAR(13) + NCHAR(10) +
N'FROM ' + QUOTENAME(s.[name]) + N'.' + QUOTENAME(t.[name])
FROM sys.schemas s
JOIN sys.tables t ON s.schema_id = t.schema_id
JOIN sys.columns c ON t.object_id = c.object_id
WHERE c.[name] = N'Email'
FOR XML PATH(N''),TYPE).value(N'.','nvarchar(MAX)'),1,13,N'') + N';';
PRINT @SQL;
EXEC sp_executesql @SQL;
SELECT *
FROM #Email;
DROP TABLE #Email;
这将创建一个动态语句,该语句针对具有列UNION ALL
的每个表(在当前数据库中)创建一个Email
查询,并将值插入到所述临时表中。然后,它从临时表中返回所说的值(然后处理该表,因为我实际上并不知道您将如何处理它)。