Question

我解析XML时出现以下错误

org.apache.harmony.xml.ExpatParser$ParseException: At line 1, column 0: no element found
04-01 22:23:13.661: WARN/System.err(628):     at org.apache.harmony.xml.ExpatParser.finish(ExpatParser.java:553)
04-01 22:23:13.661: WARN/System.err(628):     at org.apache.harmony.xml.ExpatParser.parseDocument(ExpatParser.java:483)
04-01 22:23:13.672: WARN/System.err(628):     at org.apache.harmony.xml.ExpatReader.parse(ExpatReader.java:320)
04-01 22:23:13.672: WARN/System.err(628):     at org.apache.harmony.xml.ExpatReader.parse(ExpatReader.java:277)

这是我的代码

 url= new URL(queryString);         
SAXParserFactory spf = SAXParserFactory.newInstance();
SAXParser sp = spf.newSAXParser();
XMLReader xr = sp.getXMLReader();
PersonHandler myExampleHandler = new PersonHandler();
xr.setContentHandler(myExampleHandler);
xr.parse(new InputSource(url.openStream()));

我两天都在打屁股。任何人都可以帮我解决问题..

XML结构

<xml>
  <item>
    <queryType>compare-celebrity</queryType>
    <memberID>43</memberID>
    <memberName>Sachin</memberName>
    <memberSurname>Ramesh</memberSurname>
    <memberPersonalityType>[Red-Blue] Double</memberPersonalityType>
    <celebrityID>118</celebrityID>
    <celebrityName>Brad Pitt</celebrityName>
    <thumbnail>brad-pitt-1299831254.jpeg</thumbnail>
  </item>
</xml>

Answer 1

似乎xml is not a valid element name。

以字符串“xml”开头的名称，或者与(('X'|'x') ('M'|'m') ('L'|'l'))匹配的任何字符串的名称，都保留用于本规范的此版本或将来版本中的标准化。

为根元素使用不同的名称：

<items>
  <item>
    <queryType>compare-celebrity</queryType>
    <memberID>43</memberID>
    <memberName>Sachin</memberName>
    <memberSurname>Ramesh</memberSurname>
    <memberPersonalityType>[Red-Blue] Double</memberPersonalityType>
    <celebrityID>118</celebrityID>
    <celebrityName>Brad Pitt</celebrityName>
    <thumbnail>brad-pitt-1299831254.jpeg</thumbnail>
  </item>
</items>

Android中的SAX Parser？

1 个答案: