Question

我是PHP和MySQL的新手。我正在Cphalcon框架上构建自己的动漫CMS，但与多对多的关系存在一些问题，并且无法正确查询。

我在MariaDB上有3个表：

动漫：

id
title
slug
cover

季节：

id
name
animeId

情节：

id
animeId
seasonsId
name
cover

还有phalcon的3种型号：

动漫：

<?php
namespace LearnPhalcon\Models;

use Phalcon\Mvc\Model;
use Phalcon\Validation;
use Phalcon\Validation\Validator\Uniqueness;


class Anime extends Model
{

  public $id;

  public $title;

  public function initialize()
  {
    $this->hasMany('id', __NAMESPACE__ . '\Seasons', 'animeId', [
        'alias' => 'seasons'
    ]);
    $this->hasMany('id', __NAMESPACE__ . '\Episodes', 'animeId', [
        'alias' => 'episodes'
    ]);
  }

}

季节：

<?php
namespace LearnPhalcon\Models;

use Phalcon\Mvc\Model;
use Phalcon\Validation;
use Phalcon\Validation\Validator\Uniqueness;



class Seasons extends Model
{
  public $id;

  public $name;

  public function initialize()
  {
    $this->belongsTo('id', __NAMESPACE__ . '\Anime', 'id', [
        'alias' => 'anime'
    ]);
    $this->hasMany('id', __NAMESPACE__ . '\Episodes', 'seasonsId', [
        'alias' => 'episodes'
    ]);
  }

}

情节：

<?php
namespace LearnPhalcon\Models;

use Phalcon\Mvc\Model;
use Phalcon\Validation;
use Phalcon\Validation\Validator\Uniqueness;


class Episodes extends Model
{
  public $id;

  public $name;


  public function initialize()
  {
    $this->belongsTo('id', __NAMESPACE__ . '\Anime', 'id', [
        'alias' => 'anime'
    ]);
    $this->belongsTo('id', __NAMESPACE__ . '\Seasons', 'id', [
        'alias' => 'seasons'
    ]);
  }

}

索引控制器内部的操作：

public function aniAction($slug)
    {
      $slug = $this->dispatcher->getParam('slug');
      $ani = Anime::findFirst(array(
      'slug = :slug:',
      'bind' => array(
      'slug' => $slug
      )));


      if ($ani === false) {
       $this->dispatcher->forward(array(
         'controller' => 'Error',
         'action' => 'ops'
        ));
      }

     $this->view->setVar('ani', $ani);
     $this->view->setTemplateBefore('public');
    }

视图：

  {% for seasons in ani.seasons %}
    {{ seasons.name }}
    <br/>
    {% for episodes in seasons.episodes %}
      {{ episodes.name }}
      <br/>
    {% endfor %}
  {% endfor %}

实际上该代码有效，但是它只返回第一季的情节，而不是每个季节的情节

数据库示例：

动漫：

 ID: 1
 Title: Test Anime
 Slug: test-anime
 Cover: /var/uploads/test.png

季节：

--------------------
     ID: 1
     Name: Season 1
     animeId: 1
--------------------
     ID: 2
     Name: Season 2
     animeId: 1
--------------------

情节：

--------------------
ID: 1
animeId: 1
seasonsId: 1
name: Test Name
cover: n/d
---------------------
ID: 2
animeId: 1
seasonsId: 1
name: Test Name2
cover: n/d
---------------------
ID: 3
animeId: 1
seasonsId: 2
name: Test Name3
cover: n/d
---------------------

从实际的测试操作中，我得到了HTML：

Season 1
Test Name
Test Name2
Season 2 
(and here nothing)
should be Test Name3?

Answer 1

如果您要问如何建立多对多关系

动漫：

$this->hasManyToMany('id',__NAMESPACE__ . '\Episodes','animeId','seasonsId',__NAMESPACE__ . '\Seasons','id',['alias'=>'Seasons']);

季节：

$this->hasManyToMany('id',__NAMESPACE__ . '\Episodes','seasonsId','animeId',__NAMESPACE__ . '\Anime','id',['alias'=>'Anime']);

Phalcon关系很多，无法正确查询

1 个答案: