Question

这是我的代码（适用于hang子手游戏）：

import random, os

def main():

  print("******THIS IS HANGMAN******")
  print("1. Play Game ")
  print("2. Quit Game ")
  choice = input("Please enter option 1 or 2")

  if choice == "1":
     words = ["school", "holiday", "computer", "books"]
     word = random.choice(words)
     guess = ['_'] * len(word)
     guesses = 7

     while '_' in guess and guesses > 0:
         print(' '.join(guess))
         character = input('Enter character: ')

         if len(character) > 1:
             print('Only enter one character.')
             continue

         if character not in word:
             guesses -= 1

         for i, x in enumerate(word):
             if x == character:
                 guess[i] = character

         if guesses == 0:
             print('You LOST!')
             break

         else:
             print('You have only', guesses, 'chances left to win.')

     else:
         print('You won')

  elif choice == "2":
      os.system("cls")
      main()

  else:
    print("that is not a valid option")

main()

我尝试过os.system("clear")，但是它不能清除屏幕，我希望它清除整个屏幕，但是（cls）使它再次打印菜单，而（clear）除了清除2以外什么也没做。如果我缺少明显的东西，可能是因为我是python新手。

Answer 1

它再次打印菜单，因为您再次调用main()而不是仅在此停靠。 :-)

elif choice == "2":
      os.system("cls")
      main() # <--- this is the line that causes issues

现在可以进行清理了，os.system("clear")在Windows上运行，os.system("cls")在Linux / OS X上运行here。

此外，您的程序当前还会告诉用户是否不支持他们的选择，但不会提供第二次机会。您可能会遇到这样的事情：

def main():

  ...

  while True:
      choice = input("Please enter option 1 or 2")
      if choice not in ("1", "2"):
          print("that is not a valid option")
      else:
          break

  if choice == "1":
      ...

  elif choice == "2":
      ...

main()

如何在Python 3中清除屏幕？

1 个答案: